Learn Extracted exam questions AP Biology 2022 Free Response
2022 Free Response
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The binding of an extracellular ligand to a G protein-coupled receptor in the plasma membrane of a cell triggers intracellular signaling (Figure 1, A). After ligand binding, GTP replaces the GDP that is bound to Gs$\alpha$, a subunit of the G protein (Figure 1, B). This causes Gs$\alpha$ to activate other cellular proteins, including adenylyl cyclase that converts ATP to cyclic AMP (cAMP). The cAMP activates protein kinases (Figure 1, C). In cells that line the small intestine, a cAMP-activated protein kinase causes further signaling that ultimately results in the secretion of chloride ions ($\text{Cl}^-$) from the cells. Under normal conditions, Gs$\alpha$ hydrolyzes GTP to GDP, thus inactivating adenylyl cyclase and stopping the signal (Figure 1, A).
[Figure 1: A cyclic diagram showing G protein-coupled receptor signaling in an intestinal cell membrane, with three stages labeled A, B, C connected in a cycle. Stage A: an "Extracellular Ligand" binds to a "Receptor" in the "Plasma Membrane"; the receptor is coupled to an inactive "G Protein" (with GDP bound) next to inactive "Adenylyl Cyclase"; GTP is shown converting the complex forward, releasing GDP, moving to stage B. Stage B: the "G Protein (Active)" is shown bound to GTP, moving to stage C. Stage C: "Adenylyl Cyclase (Active)" converts ATP to cAMP; GTP is bound to the G protein alpha subunit; cAMP activates "Protein Kinase (Inactive)" to become "Protein Kinase (Active)", which leads to "$\text{Cl}^-$ Secretion by Cell"; a $P_i$ arrow returns from stage C back to stage A, representing hydrolysis of GTP to GDP that inactivates adenylyl cyclase and restarts the cycle at A.]
Figure 1. Under normal conditions, ligand binding to a G protein-coupled receptor results in chloride ion transport from an intestinal cell.
Individuals infected with the bacterium Vibrio cholerae experience severe loss of water from the body (dehydration). This is due to the effects of the bacterial cholera toxin that enters intestinal cells. Scientists studied the effects of cholera toxin on four samples of isolated intestinal cell membranes containing the G protein-related signal transduction components shown in Figure 1. GTP was added to samples II and IV only; cholera toxin was added to samples III and IV only. The scientists then measured the amount of cAMP produced by the adenylyl cyclase in each sample (Table 1).
TABLE 1. AMOUNT OF cAMP PRODUCED FROM INTESTINAL CELL MEMBRANES IN THE ABSENCE OR PRESENCE OF CHOLERA TOXIN
| Sample | GTP | Cholera Toxin | Rate of cAMP Production (pmol per mg adenylyl cyclase per min) |
|---|---|---|---|
| I | $-$ | $-$ | 0.5 |
| II | $+$ | $-$ | 10.0 |
| III | $-$ | $+$ | 0.5 |
| IV | $+$ | $+$ | 127.0 |
present, +; absent, $-$
Describe one characteristic of a membrane that requires a channel be present for chloride ions to passively cross the membrane. Explain why the movement of chloride ions out of intestinal cells leads to water loss.
Identify an independent variable in the experiment. Identify a negative control in the experiment. Justify why the scientists included Sample III as a control treatment in the experiment.
Based on the data, describe the effect of cholera toxin on the synthesis of cAMP. Calculate the percent change in the rate of cAMP production due to the presence of cholera toxin in sample IV compared with sample II.
A drug is designed to bind to cholera toxin before it crosses the intestinal cell membrane. Scientists mix the drug with cholera toxin and then add this mixture and GTP to a sample of intestinal cell membranes. Predict the rate of cAMP production in pmol per mg adenylyl cyclase per min if the drug binds to all of the toxin. In a separate experiment, scientists engineer a mutant adenylyl cyclase that cannot be activated by Gs$\alpha$. The scientists claim that cholera toxin will not cause excessive water loss from whole intestinal cells that contain the mutant adenylyl cyclase. Justify this claim.
During meiosis, double-strand breaks occur in chromatids. The breaks are either repaired by the exchange of genetic material between homologous nonsister chromatids, which is the process known as crossing over (Figure 1A), or they are simply repaired without any crossing over (Figure 1B). Plant breeders developing new varieties of corn are interested in determining whether, in corn, a correlation exists between the number of meiotic double-strand chromatid breaks and the number of crossovers.
[Figure 1: two diagrams of paired homologous chromosomes (each shown as two X-shaped sister-chromatid pairs, one gray and one white, joined at a chiasma near the bottom). Panel A: shows a double-strand break being repaired WITH crossing over — the chromatid pair undergoes an intermediate exchange step (crossed strands shown) and resolves into two chromosomes each with a mix of gray and white chromatid segments. Panel B: shows a double-strand break repaired WITHOUT crossing over — the chromatid pair resolves directly back into the original all-gray and all-white chromosomes with no exchange of segments.]
Figure 1. Double-strand breaks in chromatids are repaired with crossing over (A) or without crossing over (B).
Using specialized staining and microscopy techniques, scientists counted the number of double-strand chromatid breaks and the number of crossovers in the same number of meiotic gamete-forming cells of six inbred strains of corn (Table 1).
TABLE 1. NUMBER OF CHROMATID DOUBLE-STRAND BREAKS AND AVERAGE NUMBER OF CROSSOVERS IN INBRED STRAINS OF CORN
| Strain of Corn | Number of Double-Strand Breaks | Average Number of Crossovers ($\pm 2\text{SE}_{\bar{x}}$) |
|---|---|---|
| I | 710 | $19.5 \pm 0.5$ |
| II | 650 | $18.0 \pm 0.7$ |
| III | 600 | $17.5 \pm 1.0$ |
| IV | 510 | $16.0 \pm 1.0$ |
| V | 425 | $14.0 \pm 0.5$ |
| VI | 325 | $11.0 \pm 1.5$ |
The double-strand breaks occur along the DNA backbone. Describe the process by which the breaks occur.
Using the template in the space provided for your response, construct an appropriately labeled graph that represents the data in Table 1 and allows examination of a possible correlation between double-strand breaks and crossovers. Based on the data, determine whether corn strains I, II, and III differ in their average number of crossovers.
Based on the data, describe the relationship between the average number of double-strand breaks and the average number of crossovers in the strains of corn analyzed in the experiment.
Crossing over (Figure 1A) creates physical connections that are required for proper separation of homologous chromosomes during meiosis. A diploid cell with four pairs of homologous chromosomes undergoes meiosis to produce four haploid cells. Crossing over occurs between only three of the pairs. Predict the number of chromosomes most likely present in each of the four haploid cells. Provide reasoning to justify your prediction. Explain how plant breeders can use the information in Table 1 to help develop new varieties of corn.
Fireflies emit light when the enzyme luciferase catalyzes a reaction in which its substrate, D-luciferin, reacts to form oxyluciferin and other products (Figure 1). In order to determine the optimal temperature for this enzyme, scientists added ATP to a solution containing D-luciferin, luciferase, and other substances needed for the reaction. They then measured the amount of light emitted during the first three seconds of the reaction when it was carried out at different temperatures.
Figure 1. Light is emitted as a result of the reaction catalyzed by luciferase.
Describe a characteristic of the luciferase enzyme that allows it to catalyze the reaction.
Identify the dependent variable in the experiment.
State the null hypothesis for the experiment.
A student claims that, as temperature increases, there will be an increase in the amount of light given off by the reaction in the first three seconds. Support the student's claim.
Existing isolated brook trout populations in Newfoundland, Canada, were once part of a larger population that was fragmented at the end of the most recent glaciation period about 10,000 to 12,000 years ago. Researchers investigated 14 naturally separated stream populations of brook trout. They found that the populations are all genetically distinct and show differences in morphology.
Describe the prezygotic barrier that results in these genetically distinct populations.
Brook trout with longer fins are able to swim faster than brook trout with shorter fins. In one of the Newfoundland streams, the main prey of the brook trout evolved to move faster. For brook trout living in this stream, explain the difference in fitness between longer-finned individuals and shorter-finned individuals.
If two morphologically and behaviorally distinct populations of brook trout remain isolated for many generations, predict the likely impact on both populations.
Researchers claim that there are more genetic differences between any two current brook trout populations than there are between any single current population and the ancestral brook trout population from which all the trout are descended. Provide reasoning to justify their claim.
The following models represent all the interacting species in two different communities with some of the same species and feeding relationships. These models assume that both communities have the same initial biomass. The models can be used to understand the effects of human activities on the communities.
[Figure 1: two food-web diagrams side by side, "Community A" and "Community B", arranged in four horizontal trophic-level rows (top to bottom): Tertiary Consumers (TC), Secondary Consumers (SC), Primary Consumers (PC), Primary Producers (PP). Community A: PP1, PP2, PP3 at the base; arrows go PP1→PC1, PP1→PC2, PP2→PC2, PP2→PC3, PP3→PC3, PP3→PC4; then PC1→SC1, PC2→SC1, PC2→SC2, PC3→SC2, PC3→SC3, PC4→SC3; then SC1→TC1, SC2→TC1, SC2→TC2, SC3→TC2. Community B: PP1 and PP3 at the base (no PP2); arrows go PP1→PC2, PP3→PC3; then PC2→SC2, PC3→SC2; then SC2→TC2.]
Figure 1. Models of two different communities with some of the same species
Describe a characteristic of a community that makes a species invasive in that community but not invasive in a different community.
Explain why removing species PP1 will have a greater effect on community B than on community A.
An invasive species (INV) that eats individuals of species SC2 is introduced into community B. Using the template in the space provided for your response, for community B, indicate the feeding relationship for this invasive species by correctly placing INV to represent the invasive species and an arrow to represent the feeding relationship within community B.
Explain how human activities that add toxins to the soil could change a community with many species at each trophic level, such as community A, into a community with few species at each trophic level, such as community B.
Researchers are studying the use of RNA vaccines to protect individuals against certain diseases. To develop the vaccines, particular cells are first removed from an individual. Then mRNAs coding for specific proteins from a pathogen are introduced into the cells. The altered cells are injected back into the individual, where the cells make the proteins encoded by the introduced mRNAs. The individual then produces an immune response to the proteins that will help to protect the individual from developing a disease if exposed to the pathogen in the future.
When introduced into cells, the mRNAs used for vaccines must be stable so that they are not degraded before the encoded proteins are produced. Researchers developed several modified caps that they hypothesized might make the introduced mRNAs more stable than mRNAs with the normal GTP cap. To test the effect of the modified caps, the researchers produced mRNAs that differed only in their cap structure (no cap, the normal cap, or modified caps I, II, or III). They introduced the same amount of each mRNA to different groups of cells and measured the amount of time required for half of the mRNAs to degrade (mRNA half-life) and the total amount of protein translated from the mRNAs (Table 1).
TABLE 1. EFFECT OF mRNA CAP STRUCTURE ON mRNA HALF-LIFE AND PROTEIN TRANSLATED FROM THE INTRODUCED mRNA
| 5' Cap Structure | mRNA Half-Life $\pm 2\text{SE}_{\bar{x}}$ (hours after introduction into cells) | Total Amount of Protein Translated from mRNA $\pm 2\text{SE}_{\bar{x}}$ (relative to amount in normal cap) |
|---|---|---|
| No cap | $1.41 \pm 0.02$ | $0.011 \pm 0.000$ |
| Normal GTP cap | $16.10 \pm 1.83$ | $1.000 \pm 0.007$ |
| Modified cap I | $15.50 \pm 1.57$ | $4.777 \pm 0.042$ |
| Modified cap II | $27.00 \pm 2.85$ | $13.094 \pm 0.307$ |
| Modified cap III | $18.09 \pm 0.81$ | $6.570 \pm 0.075$ |
Based on the data, identify which cap structure is most likely to protect the end of the mRNAs from degradation.
Based on the data for the mRNAs with modified caps, describe the relationship between the mRNA half-life and the total amount of protein produced.
After examining the data on mRNA half-lives and the amount of protein produced, the researchers hypothesized that each mRNA molecule with modified cap I was translated more frequently than was each mRNA molecule with the normal GTP cap. Evaluate their hypothesis by comparing the data in Table 1.
Introduction of mRNAs into cells allows the cells to produce foreign proteins that they might not normally produce. Explain why the production of a foreign protein may be more likely from the introduction of mRNA than DNA into cells.