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Learn Extracted exam questions AP Calculus AB 2026 Free Response

2026 Free Response

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1 calculation

Male birds of a certain species arrive at a nesting area over a thirty-day period. The rate at which the male birds arrive at the nesting area at time $t$ days is modeled by a differentiable function $M$, where $M(t)$ is measured in number of birds per day. Selected values of $M(t)$ are shown in the table.

$t$ (days) 0 5 10 15 20 25 30
$M(t)$ (birds per day) 2 7 16 6 5 2 0

(Note: Your calculator should be in radian mode.)

1a calculation 2.3

Approximate $M'(7.5)$ using the average rate of change of $M$ over the interval $5 \le t \le 10$. Show the work that leads to your answer, and indicate units of measure.

1bi calculation 6.2

Use a midpoint Riemann sum with the three subintervals $[0,10]$, $[10,20]$, and $[20,30]$ to approximate $\displaystyle\int_0^{30} M(t)\,dt$. Show the work that leads to your answer.

1bii calculation 6.5

Interpret the meaning of $\displaystyle\int_0^{30} M(t)\,dt$ in the context of the problem.

1c calculation 8.3

The rate at which female birds of the same species arrive at the same nesting area, in birds per day, is modeled by the function $F$ defined as follows.

$$F(t)=\begin{cases}0 & \text{for } 0 \le t < 15 \\[4pt] 18+16\sin\!\left(\dfrac{\pi}{20}(t+15)\right) & \text{for } 15 \le t \le 45\end{cases}$$

How many female birds of this species arrive at the nesting area from $t=15$ to $t=45$? Show the setup for your calculations, and round your answer to the nearest integer.

1d calculation 1.16

On the interval $15 < t < 30$, the difference in the rates at which male and female birds of this species arrive at the nesting area can be modeled by the differentiable function $D(t)=M(t)-F(t)$, where $F$ is the function defined in part C. Is there a time $t$ in the interval $15 < t < 20$ when $D(t)=0$? Justify your answer.

2 calculation

The function $f$ is defined by $f(x)=1.43^{x}+0.57$, and the function $g$ is defined by $g(x)=\dfrac{14x+12}{x+12}$. The graphs of $f$ and $g$ intersect at the points $(1,2)$ and $(a,b)$, as shown in Figure 1.

[Figure 1: A graph with x-axis from 0 to 3+ and y-axis from 0 to 5+. The curve $y=g(x)$ and the curve $y=f(x)$ both start near $(0,1)$$(0,1.5)$, rise, and intersect at the labeled point $(1,2)$ and again at the labeled point $(a,b)$ (near $x=3$, $y \approx 3.8$), with $f$ above $g$ just after the second intersection. The region $R$ is shaded/bounded between the curve $y=g(x)$, the $x$-axis, the $y$-axis, and the vertical line $x=1$ (region labeled $R$ near the origin below $g$). The shaded region between the two curves from $x=0$ to $x=a$ is shown shaded gray between $(1,2)$ and $(a,b)$.]

For $x \ge 0$, the equation $y=g(x)$ can be rewritten as $x=h(y)=\dfrac{12y-12}{14-y}$, where $h$ is a function of $y$. The graph of $x=h(y)$ and the horizontal line $y=3.5$ are shown in Figure 2.

[Figure 2: A graph with x-axis from 0 to 3+ and y-axis from 0 to 5+. The curve $x=h(y)$ starts near $(0,1)$ and increases, crossing the horizontal line $y=3.5$ near $x=3$. The region $T$ is the region bounded by the curve $x=h(y)$, the $y$-axis, and the line $y=3.5$, labeled $T$ to the left of the curve.]

END OF PART A

2a calculation 8.4

Let $R$ be the region bounded by the graph of $g$, the $x$-axis, the $y$-axis, and the vertical line $x=1$, as shown in Figure 1. Find the area of region $R$. Show the setup for your calculations.

2b calculation 8.7

Region $R$, described in part A, is the base of a solid. For this solid, each cross section perpendicular to the $x$-axis is a rectangle whose height is $\dfrac{1}{3}$ times the length of its base in region $R$. Write, but do not evaluate, an integral expression that gives the volume of the solid.

2c calculation 8.4

The shaded region in Figure 1 is bounded by the graphs of $f$ and $g$ on the interval from $x=0$ to $x=a$. Find the area of the shaded region. Show the setup for your calculations.

2d calculation 8.9

Let $T$ be the region bounded by the graph of $x=h(y)$, the $y$-axis, and the horizontal line $y=3.5$, as shown in Figure 2. Write, but do not evaluate, an integral expression that gives the volume of the solid generated when region $T$ is revolved about the $y$-axis.

3 calculation

A pie is taken from a hot oven and put on a table. The internal temperature of the pie at time $t$ minutes can be modeled by the function $H$ that satisfies the differential equation $\dfrac{dH}{dt}=-\dfrac{1}{15}(H-20)$, where $H(t)$ is measured in degrees Celsius and $H(0)=75$. For $t>0$, it is known that $20 < H(t) < 75$.

3a calculation 7.4

Explain why the following could not be a slope field for the differential equation $\dfrac{dH}{dt}=-\dfrac{1}{15}(H-20)$.

[Slope field diagram: $H$-axis (vertical) from 30 to 70+ in increments of 10, $t$-axis (horizontal) from 0 to 25+ in increments of 5. At every grid point across the full range of $t$ shown, the line segments have the same positive slope for a given horizontal row and the slopes appear to depend only on $t$ (segments in each row are parallel and tilt more steeply positive at greater height $H$, but they do not appear to flatten toward zero as $H \to 20$ nor do the segments vary with $t$ within a row as required) — segments are drawn as short parallel dashes tilting up-and-to-the-right throughout, uniformly across each horizontal band of $H$ values, without change as $t$ increases.]

3b calculation 7.1

Find the slope of the line tangent to the graph of $H$ at time $t=0$. Show the work that leads to your answer.

3c calculation 4.65.6

It can be shown that $\dfrac{d^2H}{dt^2}=\dfrac{1}{225}(H-20)$. The line tangent to the graph of $H$ at time $t=0$ is used to approximate $H(5)$, the internal temperature of the pie at time $t=5$. Is this approximation an overestimate or an underestimate for the actual value of $H(5)$? Give a reason for your answer.

3d calculation 7.7

Use separation of variables to find an expression for $H(t)$, the particular solution to the given differential equation with initial condition $H(0)=75$.

4 calculation

Let $f$ be a twice-differentiable function on the closed interval $[-4,4]$ with $f(2)=3$. The graph of $f'$, the derivative of $f$, is shown.

[Graph of $f'$: x-axis from $-4$ to $4$, y-axis from $-1$ to $5$. The curve passes through labeled points $(-4,-0.5)$, a local minimum at $(-3,-1)$, rises through the $x$-axis between $x=-2$ and $x=-1$, continues rising to a local maximum at $(1,3)$, then decreases through $(2,1.5)$, crosses the $x$-axis at $x=3$ (touching down to a minimum of 0 at $x=3$), then rises sharply to $(4,5)$.]

4a calculation 2.62.7

For $x>0$, the function $g$ is defined by $g(x)=f(x)-\ln x$. Find $g'(2)$. Show the work that leads to your answer.

4b calculation 5.6

Find all values of $x$ on the open interval $0 < x < 3$ at which the graph of $f$ has a point of inflection. Give a reason for your answer.

4c calculation 5.35.6

For $-4 \le x \le 4$, on what open intervals, if any, is the graph of $f$ both increasing and concave down? Give a reason for your answer.

4d calculation 5.5

For $-4 \le x \le 4$, find the value of $x$ at which $f$ has an absolute minimum and the value of $x$ at which $f$ has an absolute maximum. Give reasons for your answers.

5 calculation

A remote-controlled toy car moves back and forth along a straight path so that its velocity at time $t$ is given by the function $v$, where $v(t)$ is measured in feet per second and $t$ is measured in seconds.

$$v(t)=\begin{cases}t^{4}-8t^{3}+16t^{2} & \text{for } 0 \le t \le 4 \\[4pt] 0 & \text{for } 4 < t < 6 \\[4pt] 10\cos\!\left(\dfrac{\pi}{3}t\right)-10 & \text{for } 6 \le t \le 12\end{cases}$$

The graph of $v(t)$ is shown.

[Graph of $v(t)$: t-axis from 0 to 12 in increments of 2 (labels at 2,4,6,8,10,12); v-axis unlabeled (vertical). The curve starts at the origin $(0,0)$, rises to a local maximum somewhere between $t=2$ and $t=4$, returns to and touches the $t$-axis at $t=4$, stays at $v=0$ (flat on the $t$-axis) from $t=4$ to $t=6$, then dips below the axis into a trough with minimum between $t=8$ and $t=10$, and rises back up to touch the $t$-axis at $t=12$.]

5a calculation 4.2

Find the acceleration of the car at time $t=1$ second. Show the work that leads to your answer.

5b calculation 4.2

Is the car speeding up or slowing down at time $t=1$ second? Give a reason for your answer.

5c calculation 8.2

Find the distance, in feet, that the car traveled over the time interval $0 \le t \le 4$ seconds. Show the work that leads to your answer.

5d calculation 8.2

Find the average velocity of the car over the time interval $6 \le t \le 12$ seconds. Show the work that leads to your answer.

6 calculation

The function $f$ is twice differentiable. The table gives values of $f$ and its derivative $f'$ at selected values of $x$.

$x$ 0 2 3 6
$f(x)$ $-1$ 3 8 5
$f'(x)$ $-5$ 4 9 $-2$
6a calculation 1.5

Find $\displaystyle\lim_{x\to 2} \dfrac{f(x)}{x}$, or state that the limit does not exist.

6b calculation 3.1

Let $g(x)=f(f(x))$. Find $g'(2)$. Show the work that leads to your answer.

6c calculation 3.16.7

Let $h$ be a differentiable function such that $h(0)=10$ and $h'(x)=f'(3x)$. Find $h(2)$. Show the work that leads to your answer.

6di calculation 6.4

Let $k$ be the function defined by $k(x)=\displaystyle\int_0^x t^2 f(t)\,dt$. Find $k'(x)$.

6dii calculation 3.62.8

Find $k''(3)$. Show the work that leads to your answer.

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