| Core | Supplement |
|---|---|
| 1 State the distinguishing properties of solids, liquids and gases | |
| 2 Describe the structures of solids, liquids and gases in terms of particle separation, arrangement and motion | |
| 3 Describe changes of state in terms of melting, boiling, evaporating, freezing and condensing | 5 Explain changes of state in terms of kinetic particle theory, including the interpretation of heating and cooling curves |
| 4 Describe the effects of temperature and pressure on the volume of a gas | 6 Explain, in terms of kinetic particle theory, the effects of temperature and pressure on the volume of a gas |
IGCSE Chemistry
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1 States of matter
1.1
The three states of matter
Syllabus
Source: Cambridge International syllabus
Everything around you is made of tiny particles 粒子 — these can be atoms 原子, molecules 分子, or ions 离子. The kinetic particle theory 粒子动理论 says these particles are always moving. How close the particles are, how they are arranged, and how they move decides whether matter is a solid 固体, a liquid 液体, or a gas 气体.
Properties you can observe
You do not need a microscope to tell the three states apart. They behave in different ways:
- A solid has a fixed shape and a fixed volume 体积. It does not flow and you cannot compress 压缩 it (squeeze it smaller).
- A liquid has a fixed volume but no fixed shape. It flows and takes the shape of its container. It is almost impossible to compress.
- A gas has no fixed shape and no fixed volume. It flows and spreads out to fill the whole container. A gas is easy to compress.
The table below sums up these properties. Density 密度 means how much mass 质量 is packed into a given volume.
Property Solid Liquid Gas Shape fixed takes the shape of the container fills the whole container Volume fixed fixed fills the whole container Can it be compressed? no almost none yes, easily Does it flow? no yes yes Density high high low The particle picture
The kinetic particle theory explains these properties by looking at three things: the separation 间距 of the particles (how far apart they are), their arrangement 排列 (the pattern), and their motion 运动 (how they move).
Solid Liquid Gas Separation touching, very close close together far apart Arrangement regular 规则 pattern random, no pattern random, no pattern Motion vibrate 振动 about fixed positions move and slide past each other move quickly in all directions Strong forces of attraction 引力 hold the particles together. In a solid these forces are strong enough to hold every particle in place, so a solid keeps its shape. In a liquid the forces are weaker, so particles can move around. In a gas the particles move so fast that the forces hardly act at all, so the gas spreads out.
Particles are packed and regular in a solid, close and random in a liquid, and far apart in a gasVocabulary TrainEnglish Chinese Pinyin particles 粒子 lì zi atoms 原子 yuán zi molecules 分子 fèn zǐ ions 离子 lí zi kinetic particle theory 粒子动理论 lì zi dòng lǐ lùn solid 固体 gù tǐ liquid 液体 yè tǐ gas 气体 qì tǐ volume 体积 tǐ jī compress 压缩 yā suō density 密度 mì dù mass 质量 zhì liàng separation 间距 jiān jù arrangement 排列 pái liè motion 运动 yùn dòng regular 规则 guī zé vibrate 振动 zhèn dòng forces of attraction 引力 yǐn lì 1.1
Changes of state
Ice melting to water: a change of state as the solid warms.When you heat or cool a substance, it can change from one state to another. You must know the name of each change.
Change What happens Name solid → liquid melting 熔化 melting liquid → solid freezing 凝固 freezing liquid → gas (at the surface, below the boiling point) evaporating 蒸发 evaporation liquid → gas (all through the liquid) boiling 沸腾 boiling gas → liquid condensing 凝结 condensation A pure solid melts at one fixed temperature, the melting point 熔点. A pure liquid boils at one fixed temperature, the boiling point 沸点. The same substance freezes at its melting point and condenses at its boiling point.
Heating: solid → liquid → gas; cooling reverses each changeA few substances change straight from solid to gas without melting first. This is called sublimation 升华. In the photo below, warmed solid iodine in a beaker turns directly into a purple gas; the gas then cools on the round flask of ice above and turns back into a solid.
Warmed solid iodine turns straight into a purple gas (sublimation)Explaining changes of state with the particle theory
Each change of state is really a change in the energy 能量 of the particles.
- When you heat a solid, the particles gain energy and vibrate faster. At the melting point the particles have enough energy to break away from their fixed places and slide around — the solid melts.
- When you heat a liquid, the particles move faster. At the boiling point they have enough energy to fully escape the forces of attraction and become a gas.
- Cooling does the opposite. The particles lose energy, move more slowly, and the forces of attraction pull them back together.
During a change of state the energy goes into breaking the forces of attraction, not into making the particles move faster. This is why the temperature stays the same while a substance is melting or boiling.
Heating and cooling curves
A heating curve 加热曲线 is a graph of temperature against time as you heat a substance steadily. A cooling curve 冷却曲线 is the same graph as the substance cools.
On a heating curve there are two flat (level) parts:
- The first flat part is at the melting point. Here solid and liquid are both present. The heat energy breaks the forces holding the solid together, so the temperature does not rise.
- The second flat part is at the boiling point. Here liquid and gas are both present, and the temperature again stays constant.
A cooling curve is the reverse. It has a flat part at the boiling point (the gas condenses) and a flat part at the melting point (the liquid freezes). As the particles slow down, thermal energy 热能 is released to the surroundings.
Temperature stays constant at the melting and boiling points while forces of attraction are brokenVocabulary TrainEnglish Chinese Pinyin melting 熔化 róng huà freezing 凝固 níng gù evaporating 蒸发 zhēng fā boiling 沸腾 fèi téng condensing 凝结 níng jié melting point 熔点 róng diǎn boiling point 沸点 fèi diǎn sublimation 升华 shēng huá energy 能量 néng liàng heating curve 加热曲线 jiā rè qū xiàn cooling curve 冷却曲线 lěng què qū xiàn thermal energy 热能 rè néng 1.1
Gases: temperature, pressure and volume
A gas pushes on the walls of its container. This push, spread over the area of the wall, is the pressure 压强 of the gas. Pressure comes from the gas particles hitting the walls.
Effect of temperature
If you heat a fixed mass of gas while keeping the pressure the same, its volume increases.
Using the particle theory: heating gives the particles more kinetic energy 动能, so they move faster. They hit the walls harder and more often. To keep the pressure the same, the gas must take up more space, so the volume gets bigger.
If instead the volume is fixed (a sealed, rigid container), heating the gas makes the pressure rise, because the faster particles collide 碰撞 with the walls harder and more often.
Effect of pressure
If you increase the pressure on a fixed mass of gas while keeping the temperature the same, its volume decreases. Squeezing the gas into a smaller space means the particles hit the walls more often, which is what a higher pressure means.
Vocabulary TrainEnglish Chinese Pinyin pressure 压强 yā qiáng kinetic energy 动能 dòng néng collide 碰撞 pèng zhuàng 1.2
Diffusion
Syllabus
Core Supplement 1 Describe and explain diffusion in terms of kinetic particle theory 2 Describe and explain the effect of relative molecular mass on the rate of diffusion of gases Source: Cambridge International syllabus
Diffusion 扩散 is the spreading of particles from a region where they are crowded to a region where they are spread out — that is, from high concentration 浓度 to low concentration. It happens because particles are always moving in random directions.
Diffusion explains why you can smell food from across a room: the smell particles move and mix with the air until they reach your nose. Diffusion happens in gases and in liquids, but not in solids, because solid particles cannot move from place to place.
Rate of diffusion and molecular mass
Lighter gas particles move faster than heavier ones at the same temperature. So a gas with a smaller relative molecular mass 相对分子质量 (a smaller mass for each molecule) has a faster rate 速率 of diffusion.
A classic experiment shows this. Cotton wool soaked in ammonia 氨气 ($\text{NH}_3$) is put at one end of a long glass tube. Cotton wool soaked in hydrogen chloride 氯化氢 ($\text{HCl}$) is put at the other end. Both gases diffuse along the tube and meet to form a white ring of ammonium chloride 氯化铵 ($\text{NH}_4\text{Cl}$).
$$\text{NH}_3 + \text{HCl} \rightarrow \text{NH}_4\text{Cl}$$Ammonia has $M_r = 17$ and hydrogen chloride has $M_r = 36.5$. Ammonia is lighter, so it diffuses faster and travels further along the tube. The white ring forms nearer the hydrogen chloride end.
Ammonia ($M_r=17$) is lighter, so it diffuses faster and further; the white ring forms nearer the HCl endVocabulary TrainEnglish Chinese Pinyin diffusion 扩散 kuò sàn concentration 浓度 nóng dù relative molecular mass 相对分子质量 xiāng duì fèn zǐ zhì liàng rate 速率 sù lǜ ammonia 氨气 ān qì hydrogen chloride 氯化氢 lǜ huà qīng ammonium chloride 氯化铵 lǜ huà ǎn -
2 Atoms, elements and compounds
2.1
Elements, compounds and mixtures
Syllabus
Core Supplement 1 Describe the differences between elements, compounds and mixtures Source: Cambridge International syllabus
A pure element (vanadium): elements are the simplest substances.All substances are made from about 100 simple building blocks. Knowing how they are joined lets you sort every substance into one of three groups.
- An element 元素 is a substance made of only one type of atom 原子. You cannot break it into anything simpler by a chemical reaction. Examples: copper, oxygen, carbon.
- A compound 化合物 is two or more elements chemically joined (bonded) together. The atoms are joined in a fixed ratio. Examples: water, carbon dioxide. A compound has different properties from the elements in it.
- A mixture 混合物 is two or more substances that are just mixed, not chemically joined. The parts keep their own properties and can be separated by physical methods. Example: air.
The key difference: in a compound the elements are bonded and can only be separated by chemical reactions; in a mixture they are not bonded and are easy to separate.
An element has one type of atom; a compound has different atoms bonded in a fixed ratio; a mixture is not bondedVocabulary TrainEnglish Chinese Pinyin element 元素 yuán sù atom 原子 yuán zi compound 化合物 huà hé wù mixture 混合物 hùn hé wù 2.2
Atomic structure
Syllabus
Core Supplement 1 Describe the structure of the atom as a central nucleus containing neutrons and protons surrounded by electrons in shells 2 State the relative charges and relative masses of a proton, a neutron and an electron 3 Define proton number/atomic number as the number of protons in the nucleus of an atom 4 Define mass number/nucleon number as the total number of protons and neutrons in the nucleus of an atom 5 Determine the electronic configuration of elements and their ions with proton number 1 to 20, e.g. 2,8,3 6 State that: (a) Group VIII noble gases have a full outer electron shell (b) the number of outer shell electrons is equal to the group number in Groups I to VII (c) the number of occupied electron shells is equal to the period number Source: Cambridge International syllabus
Inside the atom
Every atom has a small, dense centre called the nucleus 原子核. Around it, electrons 电子 move in shells 电子层 (energy levels). The nucleus contains two kinds of particle: protons 质子 and neutrons 中子.
An atom has a tiny nucleus of protons and neutrons, with electrons in shells around itEach particle has a relative mass and a relative charge 电荷. You must learn these values:
Particle Relative mass Relative charge proton 1 $+1$ neutron 1 $0$ electron $\frac{1}{1840}$ (almost 0) $-1$ An atom has no overall charge because it has equal numbers of protons ($+1$ each) and electrons ($-1$ each).
Proton number and mass number
Two numbers describe an atom:
- The proton number 质子数 (also called the atomic number 原子序数) is the number of protons in the nucleus. It tells you which element the atom is.
- The mass number 质量数 (also called the nucleon number 核子数) is the total number of protons and neutrons in the nucleus.
So the number of neutrons $=$ mass number $-$ proton number.
Electronic configuration
The electrons fill the shells from the inside out. The first shell holds up to 2 electrons; the next shells hold up to 8 each (for the first 20 elements). The electronic configuration 电子排布 lists how many electrons are in each shell, starting from the inside.
For example, an atom with 13 electrons has the configuration $2,8,3$. Sodium (proton number 11) is $2,8,1$. Calcium (proton number 20) is $2,8,8,2$.
The configuration links to the Periodic Table 周期表:
- A Group 族 number (Groups I to VII) equals the number of electrons in the outer shell. So $2,8,1$ is in Group I.
- A Period 周期 number equals the number of shells that hold electrons. So $2,8,1$ has three shells, so it is in Period 3.
- The noble gases 稀有气体 in Group VIII (or 0) have a full outer shell, which makes them very unreactive.
Vocabulary TrainEnglish Chinese Pinyin nucleus 原子核 yuán zǐ hé electrons 电子 diàn zi shells 电子层 diàn zi céng protons 质子 zhì zi neutrons 中子 zhōng zi charge 电荷 diàn hè proton number 质子数 zhì zi shù atomic number 原子序数 yuán zi xù shù mass number 质量数 zhì liàng shù nucleon number 核子数 hé zǐ shù electronic configuration 电子排布 diàn zi pái bù Periodic Table 周期表 zhōu qī biǎo Group 族 zú Period 周期 zhōu qī noble gases 稀有气体 xī yǒu qì tǐ 2.3
Isotopes
Syllabus
Core Supplement 1 Define isotopes as different atoms of the same element that have the same number of protons but different numbers of neutrons 3 State that isotopes of the same element have the same chemical properties because they have the same number of electrons and therefore the same electronic configuration 2 Interpret and use symbols for atoms, e.g. $^{12}_{6}\text{C}$, and ions, e.g. $^{35}_{17}\text{Cl}^-$ 4 Calculate the relative atomic mass of an element from the relative masses and abundances of its isotopes Source: Cambridge International syllabus
Isotopes 同位素 are atoms of the same element that have the same number of protons but different numbers of neutrons. Because the proton number is the same, they are the same element. Because the neutron number is different, they have different mass numbers.
You write an atom with its mass number on top and proton number below, like $^{12}_{6}\text{C}$. For an ion you add the charge, like $^{35}_{17}\text{Cl}^{-}$.
Isotopes of an element have the same chemical properties. This is because chemical reactions only involve electrons, and isotopes have the same number of electrons and the same electronic configuration. (The extra neutrons change only the mass.)
Calculating relative atomic mass
The relative atomic mass 相对原子质量 ($A_r$) of an element is the average mass of its atoms, taking into account how common each isotope is. The abundance 丰度 is the percentage of each isotope.
$$A_r = \frac{\sum (\text{isotope mass} \times \text{abundance})}{100}$$For example, chlorine is 75% $^{35}\text{Cl}$ and 25% $^{37}\text{Cl}$:
$$A_r = \frac{(35 \times 75) + (37 \times 25)}{100} = 35.5$$Vocabulary TrainEnglish Chinese Pinyin isotopes 同位素 tóng wèi sù relative atomic mass 相对原子质量 xiāng duì yuán zi zhì liàng abundance 丰度 fēng dù 2.4
Ions and ionic bonds
Syllabus
Core Supplement 1 Describe the formation of positive ions, known as cations, and negative ions, known as anions 5 Describe the giant lattice structure of ionic compounds as a regular arrangement of alternating positive and negative ions 2 State that an ionic bond is a strong electrostatic attraction between oppositely charged ions 6 Describe the formation of ionic bonds between ions of metallic and non-metallic elements, including the use of dot-and-cross diagrams 3 Describe the formation of ionic bonds between elements from Group I and Group VII, including the use of dot-and-cross diagrams 7 Explain in terms of structure and bonding the properties of ionic compounds: (a) high melting points and boiling points (b) good electrical conductivity when aqueous or molten and poor when solid 4 Describe the properties of ionic compounds: (a) high melting points and boiling points (b) good electrical conductivity when aqueous or molten and poor when solid Source: Cambridge International syllabus
An ion 离子 is an atom (or group of atoms) that has lost or gained electrons, so it has an electric charge.
- A metal atom loses electrons to form a positive ion, called a cation 阳离子.
- A non-metal atom gains electrons to form a negative ion, called an anion 阴离子.
Atoms do this to get a full outer shell, like a noble gas.
How an ionic bond forms
An ionic bond 离子键 is a strong electrostatic attraction 静电引力 between oppositely charged ions (a $+$ ion and a $-$ ion pull together).
Ionic bonds form between a metal 金属 and a non-metal 非金属. Take sodium chloride, $\text{NaCl}$. Sodium ($2,8,1$) gives its one outer electron to chlorine ($2,8,7$). Now sodium is $\text{Na}^{+}$ ($2,8$) and chlorine is $\text{Cl}^{-}$ ($2,8,8$). Both have full outer shells, and the opposite charges attract.
You can show this with a dot-and-cross diagram: draw each atom's outer-shell electrons as dots for one element and crosses for the other, then show the electron moving from the metal to the non-metal.
Sodium gives its outer electron to chlorine; both reach full outer shells and the opposite charges attract (the blue electron came from sodium)The structure and properties of ionic compounds
An ionic compound 离子化合物 is not made of separate molecules 分子. The ions pack together into a giant lattice 晶格 — a regular pattern of huge numbers of alternating 交替 positive and negative ions.
Ions pack into a giant lattice: a regular, repeating pattern of alternating positive and negative ionsThis structure explains the properties:
Property Reason high melting point 熔点 and boiling point 沸点 the strong electrostatic attraction between ions needs a lot of energy to break poor electrical conductivity 导电性 when solid the ions are fixed in place and cannot move good conductor when molten 熔融 or aqueous 水溶液 the ions are now free to move and carry charge Vocabulary TrainEnglish Chinese Pinyin ion 离子 lí zi cation 阳离子 yáng lí zi anion 阴离子 yīn lí zi ionic bond 离子键 lí zi jiàn electrostatic attraction 静电引力 jìng diàn yǐn lì metal 金属 jīn shǔ non-metal 非金属 fēi jīn shǔ ionic compound 离子化合物 lí zi huà hé wù molecules 分子 fèn zǐ lattice 晶格 jīng gé alternating 交替 jiāo tì melting point 熔点 róng diǎn boiling point 沸点 fèi diǎn electrical conductivity 导电性 dǎo diàn xìng molten 熔融 róng róng aqueous 水溶液 shuǐ róng yè 2.5
Simple molecules and covalent bonds
Syllabus
Core Supplement 1 State that a covalent bond is formed when a pair of electrons is shared between two atoms leading to noble gas electronic configurations 2 Describe the formation of covalent bonds in simple molecules, including $\text{H}_2$, $\text{Cl}_2$, $\text{H}_2\text{O}$, $\text{CH}_4$, $\text{NH}_3$ and $\text{HCl}$. Use dot-and-cross diagrams to show the electronic configurations in these and similar molecules 4 Describe the formation of covalent bonds in simple molecules, including $\text{CH}_3\text{OH}$, $\text{C}_2\text{H}_4$, $\text{O}_2$, $\text{CO}_2$ and $\text{N}_2$. Use dot-and-cross diagrams to show the electronic configurations in these and similar molecules 3 Describe in terms of structure and bonding the properties of simple molecular compounds: (a) low melting points and boiling points (b) poor electrical conductivity 5 Explain in terms of structure and bonding the properties of simple molecular compounds: (a) low melting points and boiling points in terms of weak intermolecular forces (specific types of intermolecular forces are not required) (b) poor electrical conductivity Source: Cambridge International syllabus
A model of a water molecule: atoms share electrons in covalent bonds.A covalent bond 共价键 forms when two atoms share a pair of electrons. By sharing, each atom gets a full outer shell (a noble gas configuration). Covalent bonds form between non-metal atoms.
Some molecules to know:
- $\text{H}_2$ — two hydrogen atoms share one pair of electrons (a single bond).
- $\text{Cl}_2$, $\text{HCl}$ — one shared pair each.
- $\text{H}_2\text{O}$ — oxygen shares one pair with each of two hydrogen atoms.
- $\text{NH}_3$ — nitrogen shares a pair with each of three hydrogen atoms.
- $\text{CH}_4$ — carbon shares a pair with each of four hydrogen atoms.
- $\text{O}_2$ and $\text{CO}_2$ have double bonds (two shared pairs); $\text{N}_2$ has a triple bond (three shared pairs); $\text{C}_2\text{H}_4$ and $\text{CH}_3\text{OH}$ also use shared pairs.
In a dot-and-cross diagram for a molecule, you draw the outer electrons of each atom and show which pairs are shared in the overlap between the atoms.
In a covalent bond, atoms share pairs of electrons so each reaches a full outer shellProperties of simple molecular compounds
These substances are made of small, separate molecules.
- They have low melting points and boiling points. The covalent bonds inside each molecule are strong, but the intermolecular forces 分子间作用力 (the forces between one molecule and the next) are weak, so little energy is needed to separate the molecules.
- They are poor conductors of electricity, because the molecules have no overall charge and no free electrons or ions to carry charge.
Vocabulary TrainEnglish Chinese Pinyin covalent bond 共价键 gòng jià jiàn intermolecular forces 分子间作用力 fèn zǐ jiàn zuò yòng lì 2.6
Giant covalent structures
Syllabus
Core Supplement 1 Describe the giant covalent structures of graphite and diamond 3 Describe the giant covalent structure of silicon(IV) oxide, $\text{SiO}_2$ 2 Relate the structures and bonding of graphite and diamond to their uses, limited to: (a) graphite as a lubricant and as an electrode (b) diamond in cutting tools 4 Describe the similarity in properties between diamond and silicon(IV) oxide, related to their structures Source: Cambridge International syllabus
Some covalent substances are not small molecules. Instead, millions of atoms are joined by covalent bonds into one giant covalent structure 巨型共价结构. The two you must know are both forms of carbon.
Diamond 金刚石: each carbon atom is bonded to four other carbon atoms. This makes a very strong, rigid 3-D network. Diamond is extremely hard, so it is used in cutting tools 切割工具.
Graphite 石墨: each carbon atom is bonded to only three others, forming flat layers 层. There are weak forces between the layers, so the layers can slide over each other — this makes graphite a good lubricant 润滑剂. The fourth outer electron of each carbon is free; these delocalised electrons 离域电子 can move, so graphite conducts electricity and is used as an electrode 电极.
Diamond bonds each carbon to four others (hard); graphite forms flat layers with weak forces between them (slippery)Silicon(IV) oxide 二氧化硅 ($\text{SiO}_2$) has a giant covalent structure like diamond, so it is also very hard and has a very high melting point.
Vocabulary TrainEnglish Chinese Pinyin giant covalent structure 巨型共价结构 jù xíng gòng jià jié gòu diamond 金刚石 jīn gāng shí cutting tools 切割工具 qiē gē gōng jù graphite 石墨 shí mò layers 层 céng lubricant 润滑剂 rùn huá jì delocalised electrons 离域电子 lí yù diàn zi electrode 电极 diàn jí silicon(IV) oxide 二氧化硅 èr yǎng huà guī 2.7
Metallic bonding
Syllabus
Core Supplement 1 Describe metallic bonding as the electrostatic attraction between the positive ions in a giant metallic lattice and a ‘sea’ of delocalised electrons 2 Explain in terms of structure and bonding the properties of metals: (a) good electrical conductivity (b) malleability and ductility Source: Cambridge International syllabus
A metal is a giant structure of positive ions surrounded by a 'sea' of delocalised electrons that are free to move through the whole metal. Metallic bonding 金属键 is the strong electrostatic attraction between these positive ions and the sea of electrons.
A metal is positive ions in a 'sea' of delocalised electrons that are free to move and carry chargeThis explains two key properties of metals:
- Good electrical conductivity: the delocalised electrons are free to move and carry charge through the metal.
- Malleability 展性 (can be hammered into sheets) and ductility 延性 (can be pulled into wires): the layers of positive ions can slide over each other without breaking the metallic bond, so the metal changes shape instead of shattering.
Vocabulary TrainEnglish Chinese Pinyin metallic bonding 金属键 jīn shǔ jiàn malleability 展性 zhǎn xìng ductility 延性 yán xìng -
3 Stoichiometry
Stoichiometry 化学计量 is the study of the amounts of substances in a reaction — how much reacts and how much is made. This topic is mostly about counting atoms and doing calculations.
3.1
Chemical formulae
Syllabus
Core Supplement 1 State the formulae of the elements and compounds named in the subject content 2 Define the molecular formula of a compound as the number and type of different atoms in one molecule 5 Define the empirical formula of a compound as the simplest whole number ratio of the different atoms or ions in a compound 3 Deduce the formula of a simple compound from the relative numbers of atoms present in a model or a diagrammatic representation 6 Deduce the formula of an ionic compound from the relative numbers of the ions present in a model or a diagrammatic representation or from the charges on the ions 4 Construct word equations and symbol equations to show how reactants form products, including state symbols 7 Construct symbol equations with state symbols, including ionic equations 8 Deduce the symbol equation with state symbols for a chemical reaction, given relevant information Source: Cambridge International syllabus
A formula 化学式 shows which atoms 原子 are in a substance, and how many of each. There are two kinds of formula you must know.
- The molecular formula 分子式 is the actual number of each atom in one molecule 分子. For glucose it is $\text{C}_6\text{H}_{12}\text{O}_6$.
- The empirical formula 实验式 is the simplest whole-number ratio 比例 of the atoms or ions 离子 in a compound 化合物. For glucose it is $\text{CH}_2\text{O}$.
Working out a formula
If you are given a model or diagram, just count the atoms of each element and write them as a formula.
For an ionic compound 离子化合物 you can work out the formula from the charges on the ions. The total positive charge must balance the total negative charge, because the compound has no overall charge. Some common ions:
Positive ions Negative ions $\text{Na}^{+}$, $\text{K}^{+}$, $\text{H}^{+}$ $\text{Cl}^{-}$, $\text{OH}^{-}$, $\text{NO}_3^{-}$ $\text{Mg}^{2+}$, $\text{Ca}^{2+}$, $\text{Cu}^{2+}$ $\text{O}^{2-}$, $\text{SO}_4^{2-}$, $\text{CO}_3^{2-}$ $\text{Al}^{3+}$ $\text{N}^{3-}$ For example, $\text{Na}^{+}$ and $\text{O}^{2-}$: you need two $\text{Na}^{+}$ to balance one $\text{O}^{2-}$, so the formula is $\text{Na}_2\text{O}$.
For an ionic compound, the ion charges cross over to give the formula (here $\text{Al}_2\text{O}_3$)Vocabulary TrainEnglish Chinese Pinyin stoichiometry 化学计量 huà xué jì liàng formula 化学式 huà xué shì atoms 原子 yuán zi molecular formula 分子式 fēn zǐ shì molecule 分子 fèn zǐ empirical formula 实验式 shí yàn shì ratio 比例 bǐ lì ions 离子 lí zi compound 化合物 huà hé wù ionic compound 离子化合物 lí zi huà hé wù 3.1
Writing equations
An equation shows how reactants 反应物 (the starting substances) change into products 生成物 (the substances made).
- A word equation 文字方程式 uses names: magnesium + oxygen → magnesium oxide.
- A symbol equation 化学方程式 uses formulae and must be balanced 配平 — the same number of each atom on both sides.
$$2\text{Mg} + \text{O}_2 \rightarrow 2\text{MgO}$$
A balanced symbol equation has the same number of each atom on both sidesYou add state symbols 状态符号 in brackets to show the physical state: $(s)$ solid, $(l)$ liquid, $(g)$ gas, and $(aq)$ for aqueous 水溶液 (dissolved in water).
$$\text{Zn}(s) + 2\text{HCl}(aq) \rightarrow \text{ZnCl}_2(aq) + \text{H}_2(g)$$Ionic equations
An ionic equation 离子方程式 shows only the ions that actually change. Ions that are the same on both sides are spectator ions 旁观离子 and are left out. For example, when an acid reacts with an alkali:
$$\text{H}^{+}(aq) + \text{OH}^{-}(aq) \rightarrow \text{H}_2\text{O}(l)$$Vocabulary TrainEnglish Chinese Pinyin reactants 反应物 fǎn yìng wù products 生成物 shēng chéng wù word equation 文字方程式 wén zì fāng chéng shì symbol equation 化学方程式 huà xué fāng chéng shì balanced 配平 pèi píng state symbols 状态符号 zhuàng tài fú hào aqueous 水溶液 shuǐ róng yè ionic equation 离子方程式 lí zi fāng chéng shì spectator ions 旁观离子 páng guān lí zi 3.2
Relative masses
Syllabus
Core Supplement 1 Describe relative atomic mass, $A_r$, as the average mass of the isotopes of an element compared to 1/12th of the mass of an atom of $^{12}\text{C}$ 2 Define relative molecular mass, $M_r$, as the sum of the relative atomic masses. Relative formula mass, $M_r$, will be used for ionic compounds 3 Calculate reacting masses in simple proportions. Calculations will not involve the mole concept Source: Cambridge International syllabus
A laboratory balance measures mass — the basis of mole calculations.The relative atomic mass 相对原子质量 ($A_r$) of an element 元素 is the average mass 质量 of its atoms compared to $\tfrac{1}{12}$ of the mass of one $^{12}\text{C}$ atom.
The relative molecular mass 相对分子质量 ($M_r$) is the sum of the relative atomic masses of all the atoms in the molecule. For ionic compounds we use the relative formula mass 相对式量, found the same way from the formula.
$$M_r(\text{H}_2\text{O}) = (2 \times 1) + 16 = 18$$Reacting masses by simple proportion
You can sometimes find a reacting mass without the mole. If 24 g of magnesium makes 40 g of magnesium oxide, then 12 g of magnesium (half as much) makes 20 g of magnesium oxide.
Vocabulary TrainEnglish Chinese Pinyin relative atomic mass 相对原子质量 xiāng duì yuán zi zhì liàng element 元素 yuán sù mass 质量 zhì liàng relative molecular mass 相对分子质量 xiāng duì fèn zǐ zhì liàng relative formula mass 相对式量 xiāng duì shì liàng 3.3
The mole
Syllabus
Core Supplement 2 State that the mole, mol, is the unit of amount of substance and that one mole contains $6.02 \times 10^{23}$ particles, e.g. atoms, ions, molecules; this number is the Avogadro constant 3 Use the relationship $\text{amount of substance (mol)} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}$ to calculate: (a) amount of substance (b) mass (c) molar mass (d) relative atomic mass or relative molecular/formula mass (e) number of particles, using the value of the Avogadro constant 4 Use the molar gas volume, taken as $24\text{ dm}^3$ at room temperature and pressure, r.t.p., in calculations involving gases 1 State that concentration can be measured in $\text{g/dm}^3$ or $\text{mol/dm}^3$ 5 Calculate stoichiometric reacting masses, limiting reactants, volumes of gases at r.t.p., volumes of solutions and concentrations of solutions expressed in $\text{g/dm}^3$ and $\text{mol/dm}^3$, including conversion between $\text{cm}^3$ and $\text{dm}^3$ 6 Use experimental data from a titration to calculate the moles of solute, or the concentration or volume of a solution 7 Calculate empirical formulae and molecular formulae, given appropriate data 8 Calculate percentage yield, percentage composition by mass and percentage purity, given appropriate data Source: Cambridge International syllabus
The mole 摩尔 (symbol mol) is the unit for the amount of substance 物质的量. One mole of any substance contains $6.02 \times 10^{23}$ particles 粒子 (atoms, ions or molecules). This number is the Avogadro constant 阿伏伽德罗常数.
The molar mass 摩尔质量 is the mass of one mole, in grams per mole (g/mol). Its number is the same as the $A_r$ or $M_r$. The key relationship is:
$$\text{amount (mol)} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}$$Worked example. How many moles are in 36 g of water? Molar mass of water $= 18$ g/mol.
$$n = \frac{36}{18} = 2 \text{ mol}$$To find the number of particles, multiply the moles by the Avogadro constant.
Volumes of gases
At room temperature and pressure (r.t.p.), one mole of any gas takes up the same volume 体积. This molar gas volume 摩尔气体体积 is $24 \text{ dm}^3$.
$$\text{volume of gas (dm}^3) = \text{amount (mol)} \times 24$$Concentration of solutions
The concentration 浓度 of a solution 溶液 can be given in $\text{g/dm}^3$ or in $\text{mol/dm}^3$.
$$\text{concentration (mol/dm}^3) = \frac{\text{amount of solute (mol)}}{\text{volume (dm}^3)}$$Remember to convert volume: $1 \text{ dm}^3 = 1000 \text{ cm}^3$, so divide a volume in $\text{cm}^3$ by 1000.
Moles sit at the centre: multiply going outwards, divide coming back (concentration is moles ÷ volume)Vocabulary TrainEnglish Chinese Pinyin mole 摩尔 mó ěr amount of substance 物质的量 wù zhì dì liàng particles 粒子 lì zi Avogadro constant 阿伏伽德罗常数 ā fú gā dé luó cháng shù molar mass 摩尔质量 mó ěr zhì liàng volume 体积 tǐ jī molar gas volume 摩尔气体体积 mó ěr qì tǐ tǐ jī concentration 浓度 nóng dù solution 溶液 róng yè 3.3
Doing reaction calculations
A titration measures exactly how much acid reacts with a base.Most calculations follow the same steps: change the known amount into moles, use the balanced equation to find the moles of what you want, then change back into mass, volume or concentration.
Limiting reactant
When two reactants are mixed, often one runs out first. This is the limiting reactant 限量反应物. It decides how much product can form; any other reactant is in excess (left over).
Titration calculation
In a titration 滴定 you measure the volume of one solution that reacts with another. From the volume and concentration you find the moles of one solute 溶质, then use the equation ratio to find the moles, concentration or volume of the other.
Empirical and molecular formulae from data
To find an empirical formula from masses or percentages:
- Divide each element's mass (or %) by its $A_r$.
- Divide all the answers by the smallest one to get the simplest ratio.
To find the molecular formula, compare the empirical formula mass with the real $M_r$ and multiply up.
Percentages
- Percentage yield 产率 compares how much product you actually got with the most you could get: $\dfrac{\text{actual}}{\text{theoretical}} \times 100$.
- Percentage composition by mass 质量分数 of an element $= \dfrac{\text{mass of that element in the formula}}{M_r} \times 100$.
- Percentage purity 纯度 $= \dfrac{\text{mass of pure substance}}{\text{mass of impure sample}} \times 100$.
Vocabulary TrainEnglish Chinese Pinyin limiting reactant 限量反应物 xiàn liàng fǎn yìng wù titration 滴定 dī dìng solute 溶质 róng zhì percentage yield 产率 chǎn lǜ percentage composition by mass 质量分数 zhì liàng fēn shù percentage purity 纯度 chún dù -
4 Electrochemistry
4.1
Electrolysis
Syllabus
Core Supplement 1 Define electrolysis as the decomposition of an ionic compound, when molten or in aqueous solution, by the passage of an electric current 8 Describe the transfer of charge during electrolysis to include: (a) the movement of electrons in the external circuit (b) the loss or gain of electrons at the electrodes (c) the movement of ions in the electrolyte 2 Identify in simple electrolytic cells: (a) the anode as the positive electrode (b) the cathode as the negative electrode (c) the electrolyte as the molten or aqueous substance that undergoes electrolysis 3 Identify the products formed at the electrodes and describe the observations made during the electrolysis of: (a) molten lead(II) bromide (b) concentrated aqueous sodium chloride (c) dilute sulfuric acid using inert electrodes made of platinum or carbon/graphite 9 Identify the products formed at the electrodes and describe the observations made during the electrolysis of aqueous copper(II) sulfate using inert carbon/graphite electrodes and when using copper electrodes 4 State that metals or hydrogen are formed at the cathode and that non-metals (other than hydrogen) are formed at the anode 5 Predict the identity of the products at each electrode for the electrolysis of a binary compound in the molten state 10 Predict the identity of the products at each electrode for the electrolysis of a halide compound in dilute or concentrated aqueous solution 11 Construct ionic half-equations for reactions at the anode (to show oxidation) and at the cathode (to show reduction) 6 State that metal objects are electroplated to improve their appearance and resistance to corrosion 7 Describe how metals are electroplated Source: Cambridge International syllabus
Electrolysis 电解 is the breaking down (decomposition 分解) of an ionic compound 离子化合物 — when it is molten 熔融 or in aqueous 水溶液 solution — by passing an electric current 电流 through it.
An electrolysis cell splits a compound using an electric current.It only works when the substance is molten or dissolved, because then the ions 离子 are free to move and carry the charge. A solid ionic compound cannot be electrolysed because its ions are locked in place.
Electrolysis of water: gas bubbles off at each electrode and collects in the tubes above, with about twice as much hydrogen as oxygenThe electrolytic cell
The set-up is called an electrolytic cell 电解池. Two electrodes 电极 (solid conductors) dip into the electrolyte 电解质 — the molten or aqueous substance being broken down.
- The anode 阳极 is the positive ($+$) electrode.
- The cathode 阴极 is the negative ($-$) electrode.
The electrodes are often inert 惰性 (they do not react), such as platinum 铂 or carbon/graphite 石墨.
What is formed at each electrode
There is a simple rule:
- Metals 金属 or hydrogen 氢气 are formed at the cathode.
- Non-metals 非金属 (other than hydrogen) are formed at the anode.
For aqueous solutions, the product can depend on whether the solution is dilute 稀 or concentrated 浓. Here are the three Core examples:
Electrolyte At the cathode ($-$) At the anode ($+$) molten lead(II) bromide, $\text{PbBr}_2$ lead 铅 (silvery liquid) bromine 溴 (red-brown vapour) concentrated aqueous sodium chloride hydrogen (bubbles of gas) chlorine 氯气 (pale green gas) dilute sulfuric acid 硫酸 hydrogen (bubbles of gas) oxygen 氧气 (bubbles of gas) How the charge moves
During electrolysis:
- Electrons 电子 move through the wires (the external circuit 外电路) from the power supply.
- At the cathode, positive ions gain electrons. Gaining electrons is reduction 还原.
- At the anode, negative ions lose electrons. Losing electrons is oxidation 氧化.
- Inside the electrolyte, the ions move: positive ions go to the cathode and negative ions go to the anode.
You can write a half-equation 半反应式 for each electrode. For molten lead(II) bromide:
$$\text{Pb}^{2+} + 2e^{-} \rightarrow \text{Pb} \quad (\text{cathode, reduction})$$$$2\text{Br}^{-} \rightarrow \text{Br}_2 + 2e^{-} \quad (\text{anode, oxidation})$$
In molten lead(II) bromide, $\text{Pb}^{2+}$ moves to the cathode and $\text{Br}^-$ to the anode, where each is dischargedElectrolysis of copper(II) sulfate
The product at the anode depends on the electrode:
- With inert carbon electrodes: copper 铜 forms at the cathode and oxygen forms at the anode. The blue colour of the solution slowly fades as copper is removed.
- With copper electrodes: copper forms at the cathode, while the anode itself dissolves into the solution. The blue colour stays the same. This is used to purify copper.
Electroplating
Electroplating 电镀 means covering a metal object with a thin layer of another metal. This improves its appearance and its resistance to corrosion 腐蚀 (rusting and wearing away).
To electroplate an object:
- the object to be coated is made the cathode;
- the plating metal is made the anode;
- the electrolyte is a solution containing ions of the plating metal.
To electroplate, make the object the cathode and the plating metal the anode, in a solution of the plating-metal ionsVocabulary TrainEnglish Chinese Pinyin electrolysis 电解 diàn jiě decomposition 分解 fēn jiě ionic compound 离子化合物 lí zi huà hé wù molten 熔融 róng róng aqueous 水溶液 shuǐ róng yè electric current 电流 diàn liú ions 离子 lí zi electrolytic cell 电解池 diàn jiě chí electrodes 电极 diàn jí electrolyte 电解质 diàn jiě zhì anode 阳极 yáng jí cathode 阴极 yīn jí inert 惰性 duò xìng platinum 铂 bó graphite 石墨 shí mò metals 金属 jīn shǔ hydrogen 氢气 qīng qì non-metals 非金属 fēi jīn shǔ dilute 稀 xī concentrated 浓 nóng lead 铅 qiān bromine 溴 xiù chlorine 氯气 lǜ qì sulfuric acid 硫酸 liú suān oxygen 氧气 yǎng qì electrons 电子 diàn zi external circuit 外电路 wài diàn lù reduction 还原 huán yuán oxidation 氧化 yǎng huà half-equation 半反应式 bàn fǎn yìng shì copper 铜 tóng electroplating 电镀 diàn dù corrosion 腐蚀 fǔ shí 4.2
Hydrogen–oxygen fuel cells
Syllabus
Core Supplement 1 State that a hydrogen–oxygen fuel cell uses hydrogen and oxygen to produce electricity with water as the only chemical product 2 Describe the advantages and disadvantages of using hydrogen–oxygen fuel cells in comparison with gasoline/petrol engines in vehicles Source: Cambridge International syllabus
A fuel cell 燃料电池 uses hydrogen and oxygen to make electricity directly. The only chemical product is water.
$$2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}$$
A hydrogen–oxygen fuel cell turns chemical energy straight into electricity, with water as the only productIt is useful to compare a fuel cell with a normal petrol (gasoline) engine in a vehicle.
Hydrogen–oxygen fuel cell Petrol engine Main product water only carbon dioxide and pollutants 污染物 Effect on air clean adds to air pollution Fuel storage hydrogen is hard and dangerous to store (flammable, needs high pressure) petrol is easy to store Source hydrogen may be made using fossil fuels made from crude oil Advantages of the fuel cell: the only product is water, so it does not pollute the air, and it changes chemical energy into electricity efficiently. Disadvantages: hydrogen is hard to store and transport safely, and producing the hydrogen can still use energy from fossil fuels.
Vocabulary TrainEnglish Chinese Pinyin fuel cell 燃料电池 rán liào diàn chí pollutants 污染物 wū rǎn wù -
5 Chemical energetics
5.1
Exothermic and endothermic reactions
Syllabus
Core Supplement 1 State that an exothermic reaction transfers thermal energy to the surroundings leading to an increase in the temperature of the surroundings 4 State that the transfer of thermal energy during a reaction is called the enthalpy change, $\Delta H$, of the reaction. $\Delta H$ is negative for exothermic reactions and positive for endothermic reactions 2 State that an endothermic reaction takes in thermal energy from the surroundings leading to a decrease in the temperature of the surroundings 5 Define activation energy, $E_a$, as the minimum energy that colliding particles must have to react 3 Interpret reaction pathway diagrams showing exothermic and endothermic reactions 6 Draw and label reaction pathway diagrams for exothermic and endothermic reactions using information provided, to include: (a) reactants (b) products (c) enthalpy change of the reaction, $\Delta H$ (d) activation energy, $E_a$ 7 State that bond breaking is an endothermic process and bond making is an exothermic process and explain the enthalpy change of a reaction in terms of bond breaking and bond making 8 Calculate the enthalpy change of a reaction using bond energies Source: Cambridge International syllabus
Burning wood is exothermic, releasing heat to the surroundings.In every chemical reaction, energy is transferred. The reaction is either exothermic or endothermic, depending on which way the energy moves.
- An exothermic reaction 放热反应 gives out thermal energy 热能 to the surroundings 环境. So the temperature of the surroundings goes up.
- An endothermic reaction 吸热反应 takes in thermal energy from the surroundings. So the temperature of the surroundings goes down.
Examples of exothermic reactions are combustion 燃烧 (burning a fuel) and neutralisation 中和 (an acid reacting with an alkali). An example of an endothermic reaction is the thermal decomposition 分解 of a compound (breaking it down using heat).
An exothermic reaction warms the surroundings; an endothermic reaction cools themVocabulary TrainEnglish Chinese Pinyin exothermic reaction 放热反应 fàng rè fǎn yìng thermal energy 热能 rè néng surroundings 环境 huán jìng endothermic reaction 吸热反应 xī rè fǎn yìng combustion 燃烧 rán shāo neutralisation 中和 zhōng hé decomposition 分解 fēn jiě 5.1
Enthalpy change, ΔH
The amount of thermal energy transferred in a reaction is called the enthalpy change 焓变. It is written as $\Delta H$ and has these signs:
- $\Delta H$ is negative for an exothermic reaction, because energy leaves the chemicals.
- $\Delta H$ is positive for an endothermic reaction, because energy is taken in.
Vocabulary TrainEnglish Chinese Pinyin enthalpy change 焓变 hán biàn 5.1
Activation energy
Particles do not react every time they meet. The activation energy 活化能 ($E_a$) is the smallest amount of energy that colliding 碰撞 particles 粒子 must have before they can react. It is like a hill the particles must get over before the reaction can happen.
Vocabulary TrainEnglish Chinese Pinyin activation energy 活化能 huó huà néng colliding 碰撞 pèng zhuàng particles 粒子 lì zi 5.1
Reaction pathway diagrams
A reaction pathway diagram 反应进程图 shows how the energy changes as a reaction happens. Energy is on the vertical axis, and the progress of the reaction is on the horizontal axis.
- The line starts at the energy level of the reactants 反应物.
- It rises over a 'hill' — the height of this hill is the activation energy $E_a$.
- It then falls or rises to the energy level of the products 生成物.
- The gap between the reactant level and the product level is the enthalpy change $\Delta H$.
For an exothermic reaction, the products are lower than the reactants, so energy is given out and $\Delta H$ is negative.
For an endothermic reaction, the products are higher than the reactants, so energy is taken in and $\Delta H$ is positive.
Exothermic reactions end lower than they start ($\Delta H<0$); endothermic reactions end higher ($\Delta H>0$)Vocabulary TrainEnglish Chinese Pinyin reaction pathway diagram 反应进程图 fǎn yìng jìn chéng tú reactants 反应物 fǎn yìng wù products 生成物 shēng chéng wù 5.1
Bonds and energy
Breaking and making bonds transfers energy — the flame supplies it here.A reaction involves breaking the bonds in the reactants and making new bonds in the products.
- Bond breaking 断键 takes in energy, so it is an endothermic step.
- Bond making 成键 gives out energy, so it is an exothermic step.
The bond energy 键能 is the energy needed to break one mole of a particular bond. You can use bond energies to find the enthalpy change:
$$\Delta H = (\text{energy to break all bonds}) - (\text{energy released making all bonds})$$If more energy is given out making bonds than is taken in breaking bonds, the reaction is exothermic ($\Delta H$ negative). If less energy is given out, it is endothermic ($\Delta H$ positive).
Worked example
For the reaction $\text{H}_2 + \text{Cl}_2 \rightarrow 2\text{HCl}$, use these bond energies (in kJ/mol): H–H $= 436$, Cl–Cl $= 242$, H–Cl $= 431$.
Bonds broken: one H–H and one Cl–Cl $= 436 + 242 = 678$.
Bonds made: two H–Cl $= 2 \times 431 = 862$.
$$\Delta H = 678 - 862 = -184 \text{ kJ/mol}$$The answer is negative, so this reaction is exothermic.
Breaking bonds takes energy in ($+678$); making bonds gives more out ($-862$); so $\Delta H = -184$ kJ/molVocabulary TrainEnglish Chinese Pinyin bond breaking 断键 duàn jiàn bond making 成键 chéng jiàn bond energy 键能 jiàn néng -
6 Chemical reactions
6.1
Physical and chemical changes
Syllabus
Core Supplement 1 Identify physical and chemical changes, and describe the differences between them Source: Cambridge International syllabus
Iron rusting is a chemical change — it forms a new substance.A physical change 物理变化 does not make a new substance. The substance only changes its state or shape, and the change can usually be reversed. Melting ice and dissolving sugar are physical changes.
A chemical change 化学变化 (a chemical reaction) makes one or more new substances and is usually hard to reverse. Signs of a chemical change include a colour change, a gas being given off, an energy change, or a precipitate 沉淀 (a solid) forming.
Physical change Chemical change no new substance made new substance(s) made easy to reverse usually hard to reverse e.g. melting, boiling, dissolving e.g. burning, rusting Vocabulary TrainEnglish Chinese Pinyin physical change 物理变化 wù lǐ biàn huà chemical change 化学变化 huà xué biàn huà precipitate 沉淀 chén diàn 6.2
Rate of reaction
Syllabus
Core Supplement 5 Describe collision theory in terms of: (a) number of particles per unit volume (b) frequency of collisions between particles (c) kinetic energy of particles (d) activation energy, $E_a$ 1 Describe the effect on the rate of reaction of: (a) changing the concentration of solutions (b) changing the pressure of gases (c) changing the surface area of solids (d) changing the temperature (e) adding or removing a catalyst, including enzymes 6 Describe and explain the effect on the rate of reaction of: (a) changing the concentration of solutions (b) changing the pressure of gases (c) changing the surface area of solids (d) changing the temperature (e) adding or removing a catalyst, including enzymes using collision theory 2 State that a catalyst increases the rate of a reaction and is unchanged at the end of a reaction 7 State that a catalyst decreases the activation energy, $E_a$, of a reaction 3 Describe practical methods for investigating the rate of a reaction including change in mass of a reactant or a product and the formation of a gas 8 Evaluate practical methods for investigating the rate of a reaction including change in mass of a reactant or a product and the formation of a gas 4 Interpret data, including graphs, from rate of reaction experiments Source: Cambridge International syllabus
The rate of reaction 反应速率 tells you how fast the reactants 反应物 change into products 生成物.
Collision theory
Collision theory 碰撞理论 explains what controls the rate. For a reaction to happen, the particles 粒子 must collide 碰撞, and they must collide with enough energy. The least energy they need is the activation energy 活化能 ($E_a$). A faster rate happens when the particles have successful collisions more often.
What changes the rate
Change Effect Reason (collision theory) increase concentration 浓度 of a solution faster more particles in the same volume, so collisions happen more often increase pressure 压强 of gases faster particles are pushed closer, so collisions happen more often increase surface area 表面积 of a solid faster more particles are exposed, so collisions happen more often increase temperature faster particles gain kinetic energy 动能 and move faster, so collisions are more frequent and more of them have enough energy add a catalyst 催化剂 faster the catalyst lowers the activation energy, so more collisions are successful
More particles in the same volume collide more often, so the rate is faster
Breaking a solid into a powder exposes much more surface, so the rate is fasterCatalysts
A catalyst speeds up a reaction but is not used up — it is unchanged at the end. It works by lowering the activation energy. Enzymes 酶 are biological catalysts (catalysts that work in living things).
A catalyst gives a lower activation energy so more collisions succeed; $\Delta H$ is unchangedMeasuring the rate
You can follow a reaction over time in these ways:
- Change in mass: stand the flask on a balance. If a gas escapes, the mass falls. Record the mass at regular times.
- Volume of gas: collect the gas in a gas syringe 注射器 and read its volume at regular times.
- Formation of a precipitate: in a reaction that turns cloudy, time how long it takes for a mark under the flask to disappear.
A gas syringe collects the gas given off; read its volume at regular times to follow the rateOn a graph of product against time, the line is steepest at the start (fastest rate), becomes less steep as reactants are used up, and goes flat when the reaction has finished.
The rate is fastest at the start (steepest) and the line levels off when the reaction finishesVocabulary TrainEnglish Chinese Pinyin rate of reaction 反应速率 fǎn yìng sù lǜ reactants 反应物 fǎn yìng wù products 生成物 shēng chéng wù collision theory 碰撞理论 pèng zhuàng lǐ lùn particles 粒子 lì zi collide 碰撞 pèng zhuàng activation energy 活化能 huó huà néng concentration 浓度 nóng dù pressure 压强 yā qiáng surface area 表面积 biǎo miàn jī kinetic energy 动能 dòng néng catalyst 催化剂 cuī huà jì enzymes 酶 méi syringe 注射器 zhù shè qì 6.3
Reversible reactions and equilibrium
Syllabus
Core Supplement 1 State that some chemical reactions are reversible as shown by the symbol $\rightleftharpoons$ 3 State that a reversible reaction in a closed system is at equilibrium when: (a) the rate of the forward reaction is equal to the rate of the reverse reaction (b) the concentrations of reactants and products are no longer changing 2 Describe how changing the conditions can change the direction of a reversible reaction for: (a) the effect of heat on hydrated compounds (b) the addition of water to anhydrous compounds limited to copper(II) sulfate and cobalt(II) chloride 4 Predict and explain, for a reversible reaction, how the position of equilibrium is affected by: (a) changing temperature (b) changing pressure (c) changing concentration (d) using a catalyst using information provided 5 State the symbol equation for the production of ammonia in the Haber process, $\text{N}_2\text{(g)} + 3\text{H}_2\text{(g)} \rightleftharpoons 2\text{NH}_3\text{(g)}$ 6 State the sources of the hydrogen (methane) and nitrogen (air) in the Haber process 7 State the typical conditions in the Haber process as $450\text{ }^{\circ}\text{C}$, $20\,000\text{ kPa}/200\text{ atm}$ and an iron catalyst 8 State the symbol equation for the conversion of sulfur dioxide to sulfur trioxide in the Contact process, $2\text{SO}_2\text{(g)} + \text{O}_2\text{(g)} \rightleftharpoons 2\text{SO}_3\text{(g)}$ 9 State the sources of the sulfur dioxide (burning sulfur or roasting sulfide ores) and oxygen (air) in the Contact process 10 State the typical conditions for the conversion of sulfur dioxide to sulfur trioxide in the Contact process as $450\text{ }^{\circ}\text{C}$, $200\text{ kPa}/2\text{ atm}$ and a vanadium(V) oxide catalyst 11 Explain, in terms of rate of reaction and position of equilibrium, why the typical conditions stated are used in the Haber process and in the Contact process, including safety considerations and economics Source: Cambridge International syllabus
Some reactions are reversible 可逆反应: the products can react to form the reactants again. We show this with the symbol $\rightleftharpoons$.
Changing the direction
A clear example uses hydrated 水合 and anhydrous 无水 compounds:
- Blue hydrated copper(II) sulfate, when heated, loses its water to become white anhydrous copper(II) sulfate. Adding water turns it blue again.
- Pink hydrated cobalt(II) chloride loses water when heated to become blue anhydrous cobalt(II) chloride. Adding water turns it pink again.
Adding water to the anhydrous solid (and seeing the colour return) is used as a test for water.
Equilibrium
In a closed system 密闭系统 (where nothing enters or leaves), a reversible reaction reaches equilibrium 平衡 when:
- the rate of the forward reaction 正反应 equals the rate of the reverse reaction 逆反应, and
- the concentrations of the reactants and products are no longer changing.
Changing the position of equilibrium
The position of equilibrium 平衡位置 tells you whether there are more reactants or more products. You can move it:
- Temperature: heating moves the equilibrium in the direction that takes in heat (the endothermic 吸热反应 direction); cooling moves it in the direction that gives out heat (the exothermic 放热反应 direction).
- Pressure (gases): more pressure moves the equilibrium to the side with fewer gas molecules.
- Concentration: adding more of a substance moves the equilibrium to the other side, to use it up.
- A catalyst does not move the position of equilibrium. It only helps the reaction reach equilibrium faster.
The Haber process
The Haber process 哈伯法 makes ammonia:
$$\text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g)$$- The hydrogen 氢气 comes from methane 甲烷 (natural gas); the nitrogen 氮气 comes from the air.
- Typical conditions: a temperature of $450\,{}^{\circ}\text{C}$, a pressure of about $200$ atm ($20\,000$ kPa), and an iron 铁 catalyst.
The Contact process
The Contact process 接触法 turns sulfur dioxide into sulfur trioxide:
$$2\text{SO}_2(g) + \text{O}_2(g) \rightleftharpoons 2\text{SO}_3(g)$$- The sulfur dioxide comes from burning sulfur 硫 (or roasting sulfide ores); the oxygen 氧气 comes from the air.
- Typical conditions: a temperature of $450\,{}^{\circ}\text{C}$, a pressure of about $2$ atm ($200$ kPa), and a vanadium(V) oxide 五氧化二钒 catalyst.
Why these conditions are chosen
The conditions are a compromise 折中:
- A higher pressure would give more product, but very high pressure is dangerous and expensive, so a medium pressure is used.
- A lower temperature would give more product (both forward reactions are exothermic), but the reaction would be too slow, so a fairly high temperature is used to keep a good rate.
- The catalyst speeds up the reaction without changing the position of equilibrium, which lowers cost.
Vocabulary TrainEnglish Chinese Pinyin reversible reaction 可逆反应 kě nì fǎn yìng hydrated 水合 shuǐ hé anhydrous 无水 wú shuǐ closed system 密闭系统 mì bì xì tǒng equilibrium 平衡 píng héng forward reaction 正反应 zhèng fǎn yìng reverse reaction 逆反应 nì fǎn yìng position of equilibrium 平衡位置 píng héng wèi zhì endothermic 吸热反应 xī rè fǎn yìng exothermic 放热反应 fàng rè fǎn yìng Haber process 哈伯法 hā bó fǎ hydrogen 氢气 qīng qì methane 甲烷 jiǎ wán nitrogen 氮气 dàn qì iron 铁 tiě Contact process 接触法 jiē chù fǎ sulfur 硫 liú oxygen 氧气 yǎng qì vanadium(V) oxide 五氧化二钒 wǔ yǎng huà èr fán compromise 折中 zhé zhōng 6.4
Redox
Syllabus
Core Supplement 1 Use a Roman numeral to indicate the oxidation number of an element in a compound 2 Define redox reactions as involving simultaneous oxidation and reduction 3 Define oxidation as gain of oxygen and reduction as loss of oxygen 6 Define oxidation in terms of: (a) loss of electrons (b) an increase in oxidation number 7 Define reduction in terms of: (a) gain of electrons (b) a decrease in oxidation number 4 Identify redox reactions as reactions involving gain and loss of oxygen 8 Identify redox reactions as reactions involving gain and loss of electrons 5 Identify oxidation and reduction in redox reactions 9 Identify redox reactions by changes in oxidation number using: (a) the oxidation number of elements in their uncombined state is zero (b) the oxidation number of a monatomic ion is the same as the charge on the ion (c) the sum of the oxidation numbers in a compound is zero (d) the sum of the oxidation numbers in an ion is equal to the charge on the ion 10 Identify redox reactions by the colour changes involved when using acidified aqueous potassium manganate(VII) or aqueous potassium iodide 11 Define an oxidising agent as a substance that oxidises another substance and is itself reduced 12 Define a reducing agent as a substance that reduces another substance and is itself oxidised 13 Identify oxidising agents and reducing agents in redox reactions Source: Cambridge International syllabus
Oxidation 氧化 and reduction 还原 always happen at the same time, in what is called a redox reaction 氧化还原反应. ('Redox' is short for reduction–oxidation.)
There are three ways to describe oxidation and reduction:
- Oxygen: oxidation is the gain of oxygen; reduction is the loss of oxygen.
- Electrons 电子: oxidation is the loss of electrons; reduction is the gain of electrons.
- Oxidation number 氧化数: in oxidation the oxidation number goes up; in reduction it goes down.
A useful memory aid is OIL RIG: Oxidation Is Loss, Reduction Is Gain — of electrons.
Oxidation number rules
The oxidation number is shown by a Roman numeral, as in iron(II) and iron(III). The rules are:
- An element that is not combined has an oxidation number of $0$.
- A single-atom ion has an oxidation number equal to its charge (so $\text{Na}^{+}$ is $+1$).
- The oxidation numbers in a compound add up to $0$.
- The oxidation numbers in an ion add up to the charge on the ion.
Oxidising and reducing agents
- An oxidising agent 氧化剂 oxidises another substance, and is itself reduced.
- A reducing agent 还原剂 reduces another substance, and is itself oxidised.
Some redox reactions show clear colour changes:
- Acidified potassium manganate(VII) 高锰酸钾 is purple. When it acts as an oxidising agent it is reduced, and the purple colour fades to colourless.
- Potassium iodide 碘化钾 is colourless. When it is oxidised, red-brown iodine 碘 is formed.
Potassium manganate(VII) is deep purple; as it is reduced (or diluted) the purple fades to colourlessVocabulary TrainEnglish Chinese Pinyin oxidation 氧化 yǎng huà reduction 还原 huán yuán redox reaction 氧化还原反应 yǎng huà huán yuán fǎn yìng electrons 电子 diàn zi oxidation number 氧化数 yǎng huà shù oxidising agent 氧化剂 yǎng huà jì reducing agent 还原剂 huán yuán jì potassium manganate(VII) 高锰酸钾 gāo měng suān jiǎ potassium iodide 碘化钾 diǎn huà jiǎ iodine 碘 diǎn -
7 Acids, bases and salts
7.1
Acids
Syllabus
Core Supplement 1 Describe the characteristic properties of acids in terms of their reactions with: (a) metals (b) bases (c) carbonates 2 Describe acids in terms of their effect on: (a) litmus (b) thymolphthalein (c) methyl orange 3 State that bases are oxides or hydroxides of metals and that alkalis are soluble bases 4 Describe the characteristic properties of bases in terms of their reactions with: (a) acids (b) ammonium salts 5 Describe alkalis in terms of their effect on: (a) litmus (b) thymolphthalein (c) methyl orange 6 State that aqueous solutions of acids contain $\text{H}^+$ ions and aqueous solutions of alkalis contain $\text{OH}^-$ ions 9 Define acids as proton donors and bases as proton acceptors 10 Define a strong acid as an acid that is completely dissociated in aqueous solution and a weak acid as an acid that is partially dissociated in aqueous solution 11 State that hydrochloric acid is a strong acid, as shown by the symbol equation, $\text{HCl}(\text{aq}) \rightarrow \text{H}^+(\text{aq}) + \text{Cl}^-(\text{aq})$ 12 State that ethanoic acid is a weak acid, as shown by the symbol equation, $\text{CH}_3\text{COOH}(\text{aq}) \rightleftharpoons \text{H}^+(\text{aq}) + \text{CH}_3\text{COO}^-(\text{aq})$ 7 Describe how to compare hydrogen ion concentration, neutrality, relative acidity and relative alkalinity in terms of colour and pH using universal indicator paper 8 Describe the neutralisation reaction between an acid and an alkali to produce water, $\text{H}^+(\text{aq}) + \text{OH}^-(\text{aq}) \rightarrow \text{H}_2\text{O}(l)$ Source: Cambridge International syllabus
An acid 酸 is a substance that forms hydrogen ions ($\text{H}^{+}$) when dissolved in water. Acids have three typical reactions:
- with metals 金属: acid + metal → a salt 盐 + hydrogen 氢气
- with bases: acid + base 碱 → a salt + water (this is neutralisation 中和)
- with carbonates 碳酸盐: acid + carbonate → a salt + water + carbon dioxide 二氧化碳
Indicators
An indicator 指示剂 is a dye that changes colour to show whether a solution is acidic or alkaline.
Indicator In acid In alkali litmus 石蕊 red blue thymolphthalein 百里酚酞 colourless blue methyl orange 甲基橙 red yellow Aqueous solutions of acids contain hydrogen ions 离子 ($\text{H}^{+}$). Aqueous solutions of alkalis contain hydroxide ions ($\text{OH}^{-}$).
Litmus paper: blue litmus turns red in an acid, and red litmus turns blue in an alkaliVocabulary TrainEnglish Chinese Pinyin acid 酸 suān metals 金属 jīn shǔ salt 盐 yán hydrogen 氢气 qīng qì base 碱 jiǎn neutralisation 中和 zhōng hé carbonates 碳酸盐 tàn suān yán carbon dioxide 二氧化碳 èr yǎng huà tàn indicator 指示剂 zhǐ shì jì litmus 石蕊 shí ruǐ thymolphthalein 百里酚酞 bǎi lǐ fēn tài methyl orange 甲基橙 jiǎ jī chéng ions 离子 lí zi 7.1
Bases and alkalis
Bases are oxides 氧化物 or hydroxides 氢氧化物 of metals. An alkali 可溶性碱 is a base that dissolves in water (a soluble base).
Bases have two typical reactions:
- with acids: base + acid → a salt + water (neutralisation again)
- with ammonium salts 铵盐: this releases ammonia gas.
Vocabulary TrainEnglish Chinese Pinyin oxides 氧化物 yǎng huà wù hydroxides 氢氧化物 qīng yǎng huà wù alkali 可溶性碱 kě róng xìng jiǎn ammonium salts 铵盐 ǎn yán 7.1
Strong and weak acids
An acid is a proton 质子 donor — it gives away $\text{H}^{+}$ ions (a hydrogen ion is just a proton). A base is a proton acceptor.
How strong an acid is depends on how much of it splits into ions in water:
- A strong acid 强酸 is completely dissociated 电离 (fully split into ions) in water. Hydrochloric acid 盐酸 is strong:
$$\text{HCl}(aq) \rightarrow \text{H}^{+}(aq) + \text{Cl}^{-}(aq)$$- A weak acid 弱酸 is only partly dissociated. Ethanoic acid 乙酸 is weak, so the equation uses the reversible arrow:
$$\text{CH}_3\text{COOH}(aq) \rightleftharpoons \text{H}^{+}(aq) + \text{CH}_3\text{COO}^{-}(aq)$$Note: 'strong' and 'weak' are about dissociation, not about being dilute or concentrated.
A strong acid is fully split into ions; a weak acid stays mostly as molecules (only partly dissociated)Vocabulary TrainEnglish Chinese Pinyin proton 质子 zhì zi strong acid 强酸 qiáng suān dissociated 电离 diàn lí hydrochloric acid 盐酸 yán suān weak acid 弱酸 ruò suān ethanoic acid 乙酸 yǐ suān 7.1
The pH scale
Litmus and indicators show whether a solution is acidic or alkaline.The pH scale runs from 0 to 14 and tells you how acidic or alkaline a solution is. A higher hydrogen ion concentration means a lower pH.
You can find pH using universal indicator 通用指示剂, which turns different colours:
pH Type Colour of universal indicator below 7 acidic 酸性 red / orange / yellow exactly 7 neutral 中性 green above 7 alkaline 碱性 blue / purple
Universal indicator turns red in a strong acid, green at neutral (pH 7), and purple in a strong alkaliWhen an acid and an alkali react, the $\text{H}^{+}$ and $\text{OH}^{-}$ ions join to make water:
$$\text{H}^{+}(aq) + \text{OH}^{-}(aq) \rightarrow \text{H}_2\text{O}(l)$$Vocabulary TrainEnglish Chinese Pinyin universal indicator 通用指示剂 tōng yòng zhǐ shì jì acidic 酸性 suān xìng neutral 中性 zhōng xìng alkaline 碱性 jiǎn xìng 7.2
Oxides
Syllabus
Core Supplement 1 Classify oxides as acidic, including $\text{SO}_2$ and $\text{CO}_2$, or basic, including $\text{CuO}$ and $\text{CaO}$, related to metallic and non-metallic character 2 Describe amphoteric oxides as oxides that react with acids and with bases to produce a salt and water 3 Classify $\text{Al}_2\text{O}_3$ and $\text{ZnO}$ as amphoteric oxides Source: Cambridge International syllabus
Oxides can be sorted by how they behave:
- Acidic oxides are oxides of non-metals, such as $\text{SO}_2$ and $\text{CO}_2$.
- Basic oxides are oxides of metals, such as $\text{CuO}$ and $\text{CaO}$.
- Amphoteric 两性 oxides react with both acids and bases to make a salt and water. $\text{Al}_2\text{O}_3$ and $\text{ZnO}$ are amphoteric.
So metal oxides tend to be basic and non-metal oxides tend to be acidic.
Vocabulary TrainEnglish Chinese Pinyin amphoteric 两性 liǎng xìng 7.3
Preparing salts
Syllabus
Core Supplement 1 Describe the preparation, separation and purification of soluble salts by reaction of an acid with: (a) an alkali by titration (b) excess metal (c) excess insoluble base (d) excess insoluble carbonate 4 Describe the preparation of insoluble salts by precipitation 2 Describe the general solubility rules for salts: (a) sodium, potassium and ammonium salts are soluble (b) nitrates are soluble (c) chlorides are soluble, except lead and silver (d) sulfates are soluble, except barium, calcium and lead (e) carbonates are insoluble, except sodium, potassium and ammonium (f) hydroxides are insoluble, except sodium, potassium, ammonium and calcium (partially) 3 Define a hydrated substance as a substance that is chemically combined with water and an anhydrous substance as a substance containing no water 5 Define the term water of crystallisation as the water molecules present in hydrated crystals, including $\text{CuSO}_4\bullet5\text{H}_2\text{O}$ and $\text{CoCl}_2\bullet6\text{H}_2\text{O}$ Source: Cambridge International syllabus
Whether a salt can be made by a certain method depends on whether it is soluble 可溶 (dissolves) or insoluble 不溶 (does not dissolve).
Solubility rules
Salt type Rule sodium, potassium, ammonium salts all soluble nitrates 硝酸盐 all soluble chlorides 氯化物 soluble, except lead and silver sulfates 硫酸盐 soluble, except barium, calcium and lead carbonates insoluble, except sodium, potassium and ammonium hydroxides insoluble, except sodium, potassium, ammonium and (partly) calcium Making a soluble salt
You react an acid with one of these:
- an alkali, using titration 滴定 (since both are solutions, you must measure the exact volumes);
- an excess 过量 of a metal, an insoluble base, or an insoluble carbonate.
When you use an excess of a solid, you then filter 过滤 to remove the leftover solid. Finally you evaporate 蒸发 some water and let the solution crystallise 结晶 to get the salt.
Making a soluble salt from an insoluble solid: react with excess, filter off the excess, evaporate, then crystalliseMaking an insoluble salt
An insoluble salt is made by precipitation 沉淀: mix two solutions that each contain one of the needed ions, and the insoluble salt forms as a solid. You then filter, wash and dry it.
Water in salts
- A hydrated 水合 substance is chemically joined with water.
- An anhydrous 无水 substance contains no water.
The water molecules inside hydrated crystals are called the water of crystallisation 结晶水. For example, $\text{CuSO}_4 \bullet 5\text{H}_2\text{O}$ has five water molecules for each formula unit.
Vocabulary TrainEnglish Chinese Pinyin soluble 可溶 kě róng insoluble 不溶 bù róng nitrates 硝酸盐 xiāo suān yán chlorides 氯化物 lǜ huà wù sulfates 硫酸盐 liú suān yán titration 滴定 dī dìng excess 过量 guò liàng filter 过滤 guò lǜ evaporate 蒸发 zhēng fā crystallise 结晶 jié jīng precipitation 沉淀 chén diàn hydrated 水合 shuǐ hé anhydrous 无水 wú shuǐ water of crystallisation 结晶水 jié jīng shuǐ -
8 The Periodic Table
8.1
Arrangement of the elements
Syllabus
Core Supplement 1 Describe the Periodic Table as an arrangement of elements in periods and groups and in order of increasing proton number/atomic number 2 Describe the change from metallic to non‑metallic character across a period 3 Describe the relationship between group number and the charge of the ions formed from elements in that group 4 Explain similarities in the chemical properties of elements in the same group of the Periodic Table in terms of their electronic configuration 5 Explain how the position of an element in the Periodic Table can be used to predict its properties 6 Identify trends in groups, given information about the elements Source: Cambridge International syllabus
The periodic table arranges the elements in order of atomic number.The Periodic Table 周期表 arranges all the elements 元素 in order of increasing proton number 质子数 (the atomic number 原子序数). The horizontal rows are called periods 周期 and the vertical columns are called groups 族.
A few key patterns:
- Across a period, the elements change from metals 金属 on the left to non-metals 非金属 on the right.
- The group number tells you the charge of the ions 离子 that the elements form. Group I forms $+1$ ions, Group II forms $+2$ ions, and Group VII forms $-1$ ions.
- Elements in the same group have similar chemical properties. This is because they have the same number of outer-shell electrons 电子 (the same outer electronic configuration 电子排布).
Because of these patterns, you can use an element's position to predict its properties.
Groups are the columns and periods are the rows; metals lie to the left of the staircase, non-metals to the rightVocabulary TrainEnglish Chinese Pinyin Periodic Table 周期表 zhōu qī biǎo elements 元素 yuán sù proton number 质子数 zhì zi shù atomic number 原子序数 yuán zi xù shù periods 周期 zhōu qī groups 族 zú metals 金属 jīn shǔ non-metals 非金属 fēi jīn shǔ ions 离子 lí zi electrons 电子 diàn zi electronic configuration 电子排布 diàn zi pái bù 8.2
Group I — the alkali metals
Syllabus
Core Supplement 1 Describe the Group I alkali metals, lithium, sodium and potassium, as relatively soft metals with general trends down the group, limited to: (a) decreasing melting point (b) increasing density (c) increasing reactivity 2 Predict the properties of other elements in Group I, given information about the elements Source: Cambridge International syllabus
Group I elements are the alkali metals 碱金属: lithium 锂, sodium 钠 and potassium 钾. They are soft 柔软 metals (you can cut them with a knife).
Potassium reacts violently with water, giving off hydrogen that burns with a lilac flame — reactivity increases down Group I
Every Group I atom has one electron in its outer shell, which is why they react in similar waysGoing down the group, there are clear trends 趋势:
Property Trend going down the group melting point 熔点 decreases density 密度 increases reactivity 活泼性 increases You can use these trends to predict the properties of other Group I elements. For example, rubidium (below potassium) would be even more reactive and have an even lower melting point.
Vocabulary TrainEnglish Chinese Pinyin alkali metals 碱金属 jiǎn jīn shǔ lithium 锂 lǐ sodium 钠 nà potassium 钾 jiǎ soft 柔软 róu ruǎn trends 趋势 qū shì melting point 熔点 róng diǎn density 密度 mì dù reactivity 活泼性 huó pō xìng 8.3
Group VII — the halogens
Syllabus
Core Supplement 1 Describe the Group VII halogens, chlorine, bromine and iodine, as diatomic non-metals with general trends down the group, limited to: (a) increasing density (b) decreasing reactivity 2 State the appearance of the halogens at r.t.p. as: (a) chlorine, a pale yellow-green gas (b) bromine, a red-brown liquid (c) iodine, a grey-black solid 3 Describe and explain the displacement reactions of halogens with other halide ions 4 Predict the properties of other elements in Group VII, given information about the elements Source: Cambridge International syllabus
Group VII elements are the halogens 卤素: chlorine 氯气, bromine 溴 and iodine 碘. They are diatomic 双原子 non-metals (each molecule is made of two atoms, such as $\text{Cl}_2$).
Their appearance at room temperature and pressure:
Halogen Appearance chlorine a pale yellow-green gas bromine a red-brown liquid iodine a grey-black solid Going down the group, the density increases but the reactivity decreases (the opposite trend to Group I).
Group I gets more reactive down the group, while Group VII gets less reactive down — opposite trendsDisplacement reactions
A more reactive halogen pushes out (displaces) a less reactive halide 卤化物 ion from its solution. This is a displacement reaction 置换反应.
For example, chlorine is more reactive than bromine, so chlorine displaces bromine from potassium bromide:
$$\text{Cl}_2 + 2\text{KBr} \rightarrow 2\text{KCl} + \text{Br}_2$$Vocabulary TrainEnglish Chinese Pinyin halogens 卤素 lǔ sù chlorine 氯气 lǜ qì bromine 溴 xiù iodine 碘 diǎn diatomic 双原子 shuāng yuán zi halide 卤化物 lǔ huà wù displacement reaction 置换反应 zhì huàn fǎn yìng 8.4
Transition elements
Syllabus
Core Supplement 1 Describe the transition elements as metals that: (a) have high densities (b) have high melting points (c) form coloured compounds (d) often act as catalysts as elements and in compounds 2 Describe transition elements as having ions with variable oxidation numbers, including iron(II) and iron(III) Source: Cambridge International syllabus
The transition elements 过渡元素 are the block of metals in the middle of the Periodic Table. Compared with Group I metals, they:
- have high densities;
- have high melting points;
- form coloured 有色 compounds 化合物;
- often act as catalysts, both as elements and in compounds.
They can also have variable 可变 oxidation numbers 氧化数. For example, iron 铁 forms both iron(II) and iron(III) compounds.
Vocabulary TrainEnglish Chinese Pinyin transition elements 过渡元素 guò dù yuán sù coloured 有色 yǒu sè compounds 化合物 huà hé wù variable 可变 kě biàn oxidation numbers 氧化数 yǎng huà shù iron 铁 tiě 8.5
Group VIII — the noble gases
Syllabus
Core Supplement 1 Describe the Group VIII noble gases as unreactive, monatomic gases and explain this in terms of electronic configuration Source: Cambridge International syllabus
The Group VIII noble gases 稀有气体 are unreactive 不活泼, monatomic 单原子 gases (they exist as single atoms, not as molecules).
They are unreactive because they already have a full outer shell of electrons. This makes them stable, so they do not need to gain, lose or share electrons.
Vocabulary TrainEnglish Chinese Pinyin noble gases 稀有气体 xī yǒu qì tǐ unreactive 不活泼 bù huó pō monatomic 单原子 dān yuán zi -
9 Metals
9.1
Properties of metals
Syllabus
Core Supplement 1 Compare the general physical properties of metals and non-metals, including: (a) thermal conductivity (b) electrical conductivity (c) malleability and ductility (d) melting points and boiling points 2 Describe the general chemical properties of metals, limited to their reactions with: (a) dilute acids (b) cold water and steam (c) oxygen Source: Cambridge International syllabus
Physical properties
Metals 金属 and non-metals 非金属 behave very differently:
Property Metals Non-metals thermal conductivity 导热性 (conducting heat) good poor electrical conductivity 导电性 good poor (except graphite) malleability 展性 and ductility 延性 malleable and ductile brittle 易碎 (they snap) melting point 熔点 and boiling point 沸点 usually high usually low Chemical properties
Metals react in three main ways:
- with dilute acids 酸 → a salt 盐 + hydrogen 氢气
- with cold water or steam 蒸汽 → a metal hydroxide (or oxide) + hydrogen
- with oxygen 氧气 → a metal oxide 氧化物
Vocabulary TrainEnglish Chinese Pinyin metals 金属 jīn shǔ non-metals 非金属 fēi jīn shǔ thermal conductivity 导热性 dǎo rè xìng electrical conductivity 导电性 dǎo diàn xìng malleability 展性 zhǎn xìng ductility 延性 yán xìng brittle 易碎 yì suì melting point 熔点 róng diǎn boiling point 沸点 fèi diǎn acids 酸 suān salt 盐 yán hydrogen 氢气 qīng qì steam 蒸汽 zhēng qì oxygen 氧气 yǎng qì oxide 氧化物 yǎng huà wù 9.2
Uses of metals
Syllabus
Core Supplement 1 Describe the uses of metals in terms of their physical properties, including: (a) aluminium in the manufacture of aircraft because of its low density (b) aluminium in the manufacture of overhead electrical cables because of its low density and good electrical conductivity (c) aluminium in food containers because of its resistance to corrosion (d) copper in electrical wiring because of its good electrical conductivity and ductility Source: Cambridge International syllabus
A metal is chosen for a job because of its physical properties.
- Aluminium 铝 is used to make aircraft because of its low density 密度 (it is light).
- Aluminium is used for overhead electrical cables because of its low density and good electrical conductivity.
- Aluminium is used for food containers because it resists corrosion 腐蚀.
- Copper 铜 is used for electrical wiring because of its good electrical conductivity and its ductility (it can be drawn into wires).
Vocabulary TrainEnglish Chinese Pinyin aluminium 铝 lǚ density 密度 mì dù corrosion 腐蚀 fǔ shí copper 铜 tóng 9.3
Alloys
Syllabus
Core Supplement 1 Describe an alloy as a mixture of a metal with other elements, including: (a) brass as a mixture of copper and zinc (b) stainless steel as a mixture of iron and other elements such as chromium, nickel and carbon 2 State that alloys can be harder and stronger than the pure metals and are more useful 5 Explain in terms of structure how alloys can be harder and stronger than the pure metals because the different sized atoms in alloys mean the layers can no longer slide over each other 3 Describe the uses of alloys in terms of their physical properties, including stainless steel in cutlery because of its hardness and resistance to rusting 4 Identify representations of alloys from diagrams of structure Source: Cambridge International syllabus
An alloy 合金 is a mixture 混合物 of a metal with one or more other elements.
- Brass 黄铜 is a mixture of copper and zinc 锌.
- Stainless steel 不锈钢 is a mixture of iron 铁 with other elements such as chromium 铬, nickel 镍 and carbon 碳.
Alloys are usually harder and stronger than the pure metals, which makes them more useful. For example, stainless steel is used for cutlery because it is hard and does not rust.
Why alloys are harder. In a pure metal, the atoms 原子 are all the same size, so the layers 层 can slide over each other easily. In an alloy, the different-sized atoms stop the layers from sliding, so the alloy is harder and stronger.
In an alloy, different-sized atoms stop the layers sliding past each other, so the alloy is harder than the pure metalVocabulary TrainEnglish Chinese Pinyin alloy 合金 hé jīn mixture 混合物 hùn hé wù brass 黄铜 huáng tóng zinc 锌 xīn stainless steel 不锈钢 bù xiù gāng iron 铁 tiě chromium 铬 gè nickel 镍 niè carbon 碳 tàn atoms 原子 yuán zi layers 层 céng 9.4
The reactivity series
Syllabus
Core Supplement 1 State the order of the reactivity series as: potassium, sodium, calcium, magnesium, aluminium, carbon, zinc, iron, hydrogen, copper, silver, gold 4 Describe the relative reactivities of metals in terms of their tendency to form positive ions, by displacement reactions, if any, with the aqueous ions of magnesium, zinc, iron, copper and silver 2 Describe the reactions, if any, of: (a) potassium, sodium and calcium with cold water (b) magnesium with steam (c) magnesium, zinc, iron, copper, silver and gold with dilute hydrochloric acid and explain these reactions in terms of the position of the metals in the reactivity series 5 Explain the apparent unreactivity of aluminium in terms of its oxide layer 3 Deduce an order of reactivity from a given set of experimental results Source: Cambridge International syllabus
The reactivity series 金属活动性顺序 lists metals in order of how reactive they are. Carbon and hydrogen are included for comparison:
potassium 钾, sodium 钠, calcium 钙, magnesium 镁, aluminium, carbon, zinc, iron, hydrogen, copper, silver, gold
(most reactive at the top, least reactive at the bottom)
Metals above carbon are extracted by electrolysis; those below carbon can be extracted by heating with carbonThe higher a metal is, the more easily it forms positive ions 离子. This explains its reactions:
- potassium, sodium and calcium react with cold water.
- magnesium reacts with steam (but only very slowly with cold water).
- magnesium, zinc and iron react with dilute hydrochloric acid; copper, silver and gold do not.
Displacement reactions
A more reactive metal will displace a less reactive metal from a solution of its ions (a displacement reaction 置换反应). For example, zinc displaces copper from copper(II) sulfate solution, because zinc is more reactive than copper.
The special case of aluminium
Aluminium seems less reactive than its position suggests. This is because it is covered by a thin, strong oxide layer 氧化层 that stops other substances reaching the metal underneath.
Vocabulary TrainEnglish Chinese Pinyin reactivity series 金属活动性顺序 jīn shǔ huó dòng xìng shùn xù potassium 钾 jiǎ sodium 钠 nà calcium 钙 gài magnesium 镁 měi ions 离子 lí zi displacement reaction 置换反应 zhì huàn fǎn yìng oxide layer 氧化层 yǎng huà céng 9.5
Corrosion of metals
Syllabus
Core Supplement 1 State the conditions required for the rusting of iron and steel to form hydrated iron(III) oxide 2 State some common barrier methods, including painting, greasing and coating with plastic 4 Describe the use of zinc in galvanising as an example of a barrier method and sacrificial protection 3 Describe how barrier methods prevent rusting by excluding oxygen or water 5 Explain sacrificial protection in terms of the reactivity series and in terms of electron loss Source: Cambridge International syllabus
Corrosion slowly eats away unprotected metal.Rusting 生锈 is the corrosion of iron and steel. Two things are needed for rusting: oxygen (from the air) and water. The rust 铁锈 formed is hydrated iron(III) oxide.
Sea water and air have badly rusted this iron chain — the rust is hydrated iron(III) oxide
Rusting needs both water and oxygen — the nail only rusts in the tube that has bothStopping rust
Barrier methods 隔离法 keep oxygen and water away from the iron:
- painting, greasing (covering with oil), and coating with plastic.
Galvanising 镀锌 means coating iron with a layer of zinc. This works in two ways:
- it is a barrier (the zinc keeps out air and water);
- it gives sacrificial protection 牺牲保护. Because zinc is more reactive than iron, the zinc loses electrons 电子 and corrodes instead of the iron — even if the surface is scratched.
Vocabulary TrainEnglish Chinese Pinyin rusting 生锈 shēng xiù rust 铁锈 tiě xiù barrier methods 隔离法 gé lí fǎ galvanising 镀锌 dù xīn sacrificial protection 牺牲保护 xī shēng bǎo hù electrons 电子 diàn zi 9.6
Extraction of metals
Syllabus
Core Supplement 1 Describe the ease in obtaining metals from their ores, related to the position of the metal in the reactivity series 2 Describe the extraction of iron from hematite in the blast furnace, limited to: (a) the burning of carbon (coke) to provide heat and produce carbon dioxide (b) the reduction of carbon dioxide to carbon monoxide (c) the reduction of iron(III) oxide by carbon monoxide (d) the thermal decomposition of calcium carbonate/limestone to produce calcium oxide (e) the formation of slag Symbol equations are not required 4 State the symbol equations for the extraction of iron from hematite (a) $\text{C} + \text{O}_2 \rightarrow \text{CO}_2$ (b) $\text{C} + \text{CO}_2 \rightarrow 2\text{CO}$ (c) $\text{Fe}_2\text{O}_3 + 3\text{CO} \rightarrow 2\text{Fe} + 3\text{CO}_2$ (d) $\text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2$ (e) $\text{CaO} + \text{SiO}_2 \rightarrow \text{CaSiO}_3$ 3 State that the main ore of aluminium is bauxite and that aluminium is extracted by electrolysis 5 Describe the extraction of aluminium from purified bauxite/aluminium oxide, including: (a) the role of cryolite (b) why the carbon anodes need to be regularly replaced (c) the reactions at the electrodes, including ionic half-equations Details of the purification of bauxite are not required Source: Cambridge International syllabus
How a metal is taken from its ore 矿石 depends on its place in the reactivity series. Metals below carbon can be extracted by heating with carbon (which removes the oxygen). Metals above carbon are too reactive for this and must be extracted by electrolysis 电解.
Iron from the blast furnace
Iron is extracted from its ore hematite 赤铁矿 (iron(III) oxide) in a blast furnace 高炉:
- Carbon (coke) burns in hot air to give carbon dioxide and lots of heat.
- This carbon dioxide 二氧化碳 reacts with more carbon to form carbon monoxide 一氧化碳.
- The carbon monoxide reduces the iron(III) oxide to iron (this is reduction 还原).
- Limestone 石灰石 (calcium carbonate) breaks down in the heat to form calcium oxide 氧化钙.
- The calcium oxide reacts with sandy impurities to form slag 炉渣, which is removed.
In the blast furnace, carbon monoxide reduces the iron ore, and limestone removes sandy impurities as slagAluminium by electrolysis
Aluminium is extracted from its ore bauxite 铝土矿 (purified to aluminium oxide) by electrolysis:
- The aluminium oxide is dissolved in molten cryolite 冰晶石 to lower its melting point and save energy.
- At the cathode 阴极, aluminium ions gain electrons to form aluminium metal.
- At the anode 阳极, oxygen is formed. This oxygen reacts with the hot carbon anodes and burns them away, so they must be replaced regularly.
Vocabulary TrainEnglish Chinese Pinyin ore 矿石 kuàng shí electrolysis 电解 diàn jiě hematite 赤铁矿 chì tiě kuàng blast furnace 高炉 gāo lú carbon dioxide 二氧化碳 èr yǎng huà tàn carbon monoxide 一氧化碳 yī yǎng huà tàn reduction 还原 huán yuán limestone 石灰石 shí huī shí calcium oxide 氧化钙 yǎng huà gài slag 炉渣 lú zhā bauxite 铝土矿 lǚ tǔ kuàng cryolite 冰晶石 bīng jīng shí cathode 阴极 yīn jí anode 阳极 yáng jí -
10 Chemistry of the environment
10.1
Water
Syllabus
Core Supplement 1 Describe chemical tests for the presence of water using anhydrous cobalt(II) chloride and anhydrous copper(II) sulfate 2 Describe how to test for the purity of water using melting point and boiling point 3 Explain that distilled water is used in practical chemistry rather than tap water because it contains fewer chemical impurities 4 State that water from natural sources may contain substances, including: (a) dissolved oxygen (b) metal compounds (c) plastics (d) sewage (e) harmful microbes (f) nitrates from fertilisers (g) phosphates from fertilisers and detergents 5 State that some of these substances are beneficial, including: (a) dissolved oxygen for aquatic life (b) some metal compounds provide essential minerals for life 6 State that some of these substances are potentially harmful, including: (a) some metal compounds are toxic (b) some plastics harm aquatic life (c) sewage contains harmful microbes which cause disease (d) nitrates and phosphates lead to deoxygenation of water and damage to aquatic life Details of the eutrophication process are not required 7 Describe the treatment of the domestic water supply in terms of: (a) sedimentation and filtration to remove solids (b) use of carbon to remove tastes and odours (c) chlorination to kill microbes Source: Cambridge International syllabus
Testing for water
Two chemical tests show that water is present:
- Anhydrous 无水 cobalt(II) chloride turns from blue to pink when water is added.
- Anhydrous copper(II) sulfate turns from white to blue when water is added.
These tests only show that water is there. To show that water is pure, you test its melting point 熔点 and boiling point 沸点: pure water melts at exactly $0\,{}^{\circ}\text{C}$ and boils at exactly $100\,{}^{\circ}\text{C}$. Any dissolved substance changes these values.
This is why distilled water 蒸馏水 is used in chemistry instead of tap water — it has far fewer chemical impurities 杂质.
What is in natural water
Water from rivers, lakes and the sea is not pure. It may contain dissolved oxygen 氧气, metal compounds, plastics, sewage 污水, harmful microbes 微生物, and nitrates 硝酸盐 and phosphates 磷酸盐 (which come from fertilisers and detergents).
Some of these are helpful:
- dissolved oxygen lets aquatic life 水生生物 (fish and plants) breathe;
- some metal compounds give essential minerals 矿物质.
Others are harmful:
- some metal compounds are toxic 有毒 (poisonous);
- some plastics harm aquatic life;
- sewage carries microbes that cause disease;
- nitrates and phosphates cause deoxygenation 缺氧 (loss of oxygen) in the water, which harms aquatic life.
Treating drinking water
To make water safe to drink, the water supply is treated in steps:
- sedimentation 沉降 and filtration 过滤 remove solid bits;
- passing it through carbon 碳 removes bad tastes and smells;
- chlorination 氯消毒 (adding chlorine) kills harmful microbes.
Water is made safe to drink in steps: settle out big bits, filter, remove tastes with carbon, then chlorinateVocabulary TrainEnglish Chinese Pinyin anhydrous 无水 wú shuǐ melting point 熔点 róng diǎn boiling point 沸点 fèi diǎn distilled water 蒸馏水 zhēng liú shuǐ impurities 杂质 zá zhì oxygen 氧气 yǎng qì sewage 污水 wū shuǐ microbes 微生物 wēi shēng wù nitrates 硝酸盐 xiāo suān yán phosphates 磷酸盐 lín suān yán aquatic life 水生生物 shuǐ shēng shēng wù minerals 矿物质 kuàng wù zhì toxic 有毒 yǒu dú deoxygenation 缺氧 quē yǎng sedimentation 沉降 chén jiàng filtration 过滤 guò lǜ carbon 碳 tàn chlorination 氯消毒 lǜ xiāo dú 10.2
Fertilisers
Syllabus
Core Supplement 1 State that ammonium salts and nitrates are used as fertilisers 2 Describe the use of NPK fertilisers to provide the elements nitrogen, phosphorus and potassium for improved plant growth Source: Cambridge International syllabus
Fertilisers 肥料 are added to soil to help plants grow. Ammonium salts and nitrates are common fertilisers.
NPK fertilisers contain the three elements plants need most: nitrogen 氮气, phosphorus 磷 and potassium 钾.
Vocabulary TrainEnglish Chinese Pinyin fertilisers 肥料 féi liào nitrogen 氮气 dàn qì phosphorus 磷 lín potassium 钾 jiǎ 10.3
Air quality and climate
Syllabus
Core Supplement 1 State the composition of clean, dry air as approximately 78% nitrogen, $\text{N}_2$, 21% oxygen, $\text{O}_2$ and the remainder as a mixture of noble gases and carbon dioxide, $\text{CO}_2$ 2 State the source of each of these air pollutants, limited to: (a) carbon dioxide from the complete combustion of carbon-containing fuels (b) carbon monoxide and particulates from the incomplete combustion of carbon-containing fuels (c) methane from the decomposition of vegetation and waste gases from digestion in animals (d) oxides of nitrogen from car engines (e) sulfur dioxide from the combustion of fossil fuels which contain sulfur compounds 3 State the adverse effect of these air pollutants, limited to: (a) carbon dioxide: higher levels of carbon dioxide leading to increased global warming, which leads to climate change (b) carbon monoxide: toxic gas (c) particulates: increased risk of respiratory problems and cancer (d) methane: higher levels of methane leading to increased global warming, which leads to climate change (e) oxides of nitrogen: acid rain, photochemical smog and respiratory problems (f) sulfur dioxide: acid rain 7 Describe how the greenhouse gases carbon dioxide and methane cause global warming, limited to: (a) the absorption, reflection and emission of thermal energy (b) reducing thermal energy loss to space 4 State and explain strategies to reduce the effects of these environmental issues, limited to: (a) climate change: planting trees, reduction in livestock farming, decreasing use of fossil fuels, increasing use of hydrogen and renewable energy, e.g. wind, solar (b) acid rain: use of catalytic converters in vehicles, reducing emissions of sulfur dioxide by using low-sulfur fuels and flue gas desulfurisation with calcium oxide 8 Explain how oxides of nitrogen form in car engines and describe their removal by catalytic converters, e.g. $2\text{CO} + 2\text{NO} \rightarrow 2\text{CO}_2 + \text{N}_2$ 5 Describe photosynthesis as the reaction between carbon dioxide and water to produce glucose and oxygen in the presence of chlorophyll and using energy from light 6 State the word equation for photosynthesis, carbon dioxide + water $\rightarrow$ glucose + oxygen 9 State the symbol equation for photosynthesis, $6\text{CO}_2 + 6\text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2$ Source: Cambridge International syllabus
Burning fossil fuels pollutes the air and changes the climate.Clean, dry air is approximately:
- 78% nitrogen ($\text{N}_2$)
- 21% oxygen ($\text{O}_2$)
- the rest is a mixture of noble gases 稀有气体 and carbon dioxide ($\text{CO}_2$).
Clean, dry air is about 78% nitrogen, 21% oxygen, and 1% other gases (noble gases and carbon dioxide)Air pollutants and their sources
Pollutant Main source carbon dioxide ($\text{CO}_2$) complete combustion 完全燃烧 of carbon-containing fuels carbon monoxide 一氧化碳 and particulates 颗粒物 incomplete combustion 不完全燃烧 of carbon-containing fuels methane 甲烷 rotting plants and waste gases from animal digestion oxides of nitrogen 氮氧化物 car engines sulfur dioxide burning fossil fuels 化石燃料 that contain sulfur 硫 Effects of these pollutants
- Carbon dioxide 二氧化碳 and methane are greenhouse gases 温室气体: more of them causes global warming 全球变暖, which leads to climate change 气候变化.
- Carbon monoxide is a toxic gas.
- Particulates increase the risk of respiratory 呼吸 (breathing) problems and cancer 癌症.
- Oxides of nitrogen cause acid rain 酸雨, photochemical smog 光化学烟雾 and breathing problems.
- Sulfur dioxide causes acid rain.
Reducing these problems
To slow climate change: plant trees, farm fewer animals, burn fewer fossil fuels, and use more hydrogen and renewable energy 可再生能源 such as wind and solar power.
To reduce acid rain: fit catalytic converters 催化转化器 in cars, use low-sulfur fuels, and use flue gas desulfurisation 烟气脱硫 with calcium oxide 氧化钙 to remove sulfur dioxide from waste gases.
Inside a catalytic converter is a honeycomb coated with catalyst metals; the many tiny channels give a huge surface areaHow greenhouse gases warm the Earth
Greenhouse gases such as carbon dioxide and methane let sunlight through, but they absorb the thermal energy 热能 given off by the warm Earth, and send some of it back down. This reduces the thermal energy lost to space, so the Earth gets warmer.
Greenhouse gases let sunlight through but trap some of the heat the Earth gives off, so the Earth warms upIn a car engine, the high temperature makes nitrogen and oxygen from the air react to form oxides of nitrogen. A catalytic converter removes them, for example:
$$2\text{CO} + 2\text{NO} \rightarrow 2\text{CO}_2 + \text{N}_2$$Photosynthesis
Photosynthesis 光合作用 is the opposite of combustion — it removes carbon dioxide from the air. Plants use light energy and chlorophyll 叶绿素 to turn carbon dioxide and water into glucose 葡萄糖 and oxygen:
$$6\text{CO}_2 + 6\text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2$$Vocabulary TrainEnglish Chinese Pinyin noble gases 稀有气体 xī yǒu qì tǐ complete combustion 完全燃烧 wán quán rán shāo carbon monoxide 一氧化碳 yī yǎng huà tàn particulates 颗粒物 kē lì wù incomplete combustion 不完全燃烧 bù wán quán rán shāo methane 甲烷 jiǎ wán oxides of nitrogen 氮氧化物 dàn yǎng huà wù fossil fuels 化石燃料 huà shí rán liào sulfur 硫 liú carbon dioxide 二氧化碳 èr yǎng huà tàn greenhouse gases 温室气体 wēn shì qì tǐ global warming 全球变暖 quán qiú biàn nuǎn climate change 气候变化 qì hòu biàn huà respiratory 呼吸 hū xī cancer 癌症 ái zhèng acid rain 酸雨 suān yǔ photochemical smog 光化学烟雾 guāng huà xué yān wù renewable energy 可再生能源 kě zài shēng néng yuán catalytic converters 催化转化器 cuī huà zhuǎn huà qì flue gas desulfurisation 烟气脱硫 yān qì tuō liú calcium oxide 氧化钙 yǎng huà gài thermal energy 热能 rè néng photosynthesis 光合作用 guāng hé zuò yòng chlorophyll 叶绿素 yè lǜ sù glucose 葡萄糖 pú táo táng -
11 Organic chemistry
Organic chemistry is the chemistry of carbon compounds. Carbon is special because it can join to other carbon atoms to make long chains and rings.
11.1
Formulae and key words
Syllabus
Core Supplement 1 Draw and interpret the displayed formula of a molecule to show all the atoms and all the bonds 2 Write and interpret general formulae of compounds in the same homologous series, limited to: (a) alkanes, $\text{C}_n\text{H}_{2n+2}$ (b) alkenes, $\text{C}_n\text{H}_{2n}$ (c) alcohols, $\text{C}_n\text{H}_{2n+1}\text{OH}$ (d) carboxylic acids, $\text{C}_n\text{H}_{2n+1}\text{COOH}$ 3 Identify a functional group as an atom or group of atoms that determine the chemical properties of a homologous series 7 State that a structural formula is an unambiguous description of the way the atoms in a molecule are arranged, including $\text{CH}_2=\text{CH}_2$, $\text{CH}_3\text{CH}_2\text{OH}$, $\text{CH}_3\text{COOCH}_3$ 8 Define structural isomers as compounds with the same molecular formula, but different structural formulae, including $\text{C}_4\text{H}_{10}$ as $\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_3$ and $\text{CH}_3\text{CH}(\text{CH}_3)\text{CH}_3$ and $\text{C}_4\text{H}_8$ as $\text{CH}_3\text{CH}_2\text{CH}=\text{CH}_2$ and $\text{CH}_3\text{CH}=\text{CHCH}_3$ 4 State that a homologous series is a family of similar compounds with similar chemical properties due to the presence of the same functional group 9 Describe the general characteristics of a homologous series as: (a) having the same functional group (b) having the same general formula (c) differing from one member to the next by a –CH2– unit (d) displaying a trend in physical properties (e) sharing similar chemical properties 5 State that a saturated compound has molecules in which all carbon–carbon bonds are single bonds 6 State that an unsaturated compound has molecules in which one or more carbon–carbon bonds are not single bonds Source: Cambridge International syllabus
There are several ways to write an organic molecule:
- The molecular formula 分子式 shows how many of each atom there are, for example $\text{C}_2\text{H}_6$.
- The displayed formula 结构式 shows every atom and every bond drawn out in full.
- The structural formula 结构简式 shows how the atoms are arranged without drawing every bond, for example $\text{CH}_3\text{CH}_2\text{OH}$.
- The general formula 通式 works for a whole family, for example $\text{C}_n\text{H}_{2n+2}$ for alkanes.
A homologous series 同系物 is a family of compounds with the same functional group 官能团 — the atom or group of atoms that gives the family its chemical properties. Members of a series have the same general formula, differ by a $\text{CH}_2$ unit each step, and have similar chemical properties with a gradual change in physical properties.
Series Functional group General formula alkanes C–C single bonds only $\text{C}_n\text{H}_{2n+2}$ alkenes C=C double bond $\text{C}_n\text{H}_{2n}$ alcohols –OH $\text{C}_n\text{H}_{2n+1}\text{OH}$ carboxylic acids –COOH $\text{C}_n\text{H}_{2n+1}\text{COOH}$
The alkanes are a homologous series: each member has one more $\text{CH}_2$ unit (general formula $\text{C}_n\text{H}_{2n+2}$)A saturated 饱和 compound has only single carbon–carbon bonds. An unsaturated 不饱和 compound has one or more carbon–carbon bonds that are not single (such as a C=C double bond).
A saturated compound has only single C–C bonds; an unsaturated one has a C=C double bondStructural isomers 同分异构体 are compounds with the same molecular formula but different structural formulae. For example, $\text{C}_4\text{H}_{10}$ can be a straight chain or a branched chain.
Structural isomers: butane and 2-methylpropane share the formula $\text{C}_4\text{H}_{10}$ but have different structuresVocabulary TrainEnglish Chinese Pinyin molecular formula 分子式 fēn zǐ shì displayed formula 结构式 jié gòu shì structural formula 结构简式 jié gòu jiǎn shì general formula 通式 tōng shì homologous series 同系物 tóng xì wù functional group 官能团 guān néng tuán saturated 饱和 bǎo hé unsaturated 不饱和 bù bǎo hé structural isomers 同分异构体 tóng fēn yì gòu tǐ 11.2
Naming organic compounds
Syllabus
Core Supplement 1 Name and draw the displayed formulae of: (a) methane and ethane (b) ethene (c) ethanol (d) ethanoic acid (e) the products of the reactions stated in sections 11.4–11.7 3 Name and draw the structural and displayed formulae of unbranched: (a) alkanes (b) alkenes, including but-1-ene and but-2-ene (c) alcohols, including propan-1-ol, propan-2-ol, butan-1-ol and butan-2-ol (d) carboxylic acids containing up to four carbon atoms per molecule 2 State the type of compound present, given a chemical name ending in -ane, -ene, -ol, or -oic acid or from a molecular formula or displayed formula 4 Name and draw the displayed formulae of the unbranched esters which can be made from unbranched alcohols and carboxylic acids, each containing up to four carbon atoms Source: Cambridge International syllabus
The end of the name tells you the family:
Ending Family Example -ane alkane methane, ethane -ene alkene ethene -ol alcohol ethanol -oic acid carboxylic acid ethanoic acid The start of the name tells you the number of carbon atoms: meth- = 1, eth- = 2, prop- = 3, but- = 4. For longer alkenes and alcohols, a number shows where the functional group is, for example but-1-ene and but-2-ene, or propan-1-ol and propan-2-ol.
11.3
Fuels
Syllabus
Core Supplement 1 Name the fossil fuels: coal, natural gas and petroleum 2 Name methane as the main constituent of natural gas 3 State that hydrocarbons are compounds that contain hydrogen and carbon only 4 State that petroleum is a mixture of hydrocarbons 5 Describe the separation of petroleum into useful fractions by fractional distillation 6 Describe how the properties of fractions obtained from petroleum change from the bottom to the top of the fractionating column, limited to: (a) decreasing chain length (b) higher volatility (c) lower boiling points (d) lower viscosity 7 Name the uses of the fractions as: (a) refinery gas fraction for gas used in heating and cooking (b) gasoline/petrol fraction for fuel used in cars (c) naphtha fraction as a chemical feedstock (d) kerosene/paraffin fraction for jet fuel (e) diesel oil/gas oil fraction for fuel used in diesel engines (f) fuel oil fraction for fuel used in ships and home heating systems (g) lubricating oil fraction for lubricants, waxes and polishes (h) bitumen fraction for making roads Source: Cambridge International syllabus
An oil refinery separates crude oil into useful fuels by fractional distillation.The three fossil fuels 化石燃料 are coal 煤, natural gas 天然气 and petroleum 石油 (crude oil). Methane 甲烷 is the main part of natural gas.
A hydrocarbon 碳氢化合物 is a compound made of hydrogen and carbon only. Petroleum is a mixture of many different hydrocarbons.
Fractional distillation
Petroleum is separated into useful fractions 馏分 by fractional distillation 分馏. The mixture is heated, and the different hydrocarbons turn to gas and rise up a tall fractionating column 分馏塔. The column is hot at the bottom and cool at the top, so each fraction turns back to liquid at a different height.
At an oil refinery, crude oil is separated in the tall fractionating columns you can see rising above the plant
Fractions separate by boiling point: small molecules leave the cool top, thick bitumen stays at the hot bottomGoing from the bottom to the top of the column, the fractions have:
- shorter chain length 链长 (smaller molecules);
- higher volatility 挥发性 (they turn to gas more easily);
- lower boiling points;
- lower viscosity 黏度 (they flow more easily).
Fraction Use refinery gas gas for heating and cooking gasoline / petrol fuel for cars naphtha raw material for making chemicals kerosene / paraffin jet fuel diesel oil fuel for diesel engines fuel oil fuel for ships and home heating lubricating oil lubricants, waxes and polishes bitumen 沥青 making roads Vocabulary TrainEnglish Chinese Pinyin fossil fuels 化石燃料 huà shí rán liào coal 煤 méi natural gas 天然气 tiān rán qì petroleum 石油 shí yóu methane 甲烷 jiǎ wán hydrocarbon 碳氢化合物 tàn qīng huà hé wù fractions 馏分 liú fèn fractional distillation 分馏 fēn liú fractionating column 分馏塔 fēn liú tǎ chain length 链长 liàn zhǎng volatility 挥发性 huī fā xìng viscosity 黏度 nián dù bitumen 沥青 lì qīng 11.4
Alkanes
Syllabus
Core Supplement 1 State that the bonding in alkanes is single covalent and that alkanes are saturated hydrocarbons 2 Describe the properties of alkanes as being generally unreactive, except in terms of combustion and substitution by chlorine 3 State that in a substitution reaction one atom or group of atoms is replaced by another atom or group of atoms 4 Describe the substitution reaction of alkanes with chlorine as a photochemical reaction, with ultraviolet light providing the activation energy, $E_a$, and draw the structural or displayed formulae of the products, limited to monosubstitution Source: Cambridge International syllabus
Alkanes 烷烃 have only single covalent bonds, so they are saturated hydrocarbons. They are generally unreactive. Their two important reactions are:
- Combustion 燃烧: they burn in plenty of oxygen to give carbon dioxide and water.
- Substitution with chlorine.
In a substitution reaction 取代反应, one atom (or group of atoms) is replaced by another. Alkanes react with chlorine only in ultraviolet light 紫外线 — this is a photochemical reaction 光化学反应, where the light provides the activation energy 活化能. For example:
$$\text{CH}_4 + \text{Cl}_2 \rightarrow \text{CH}_3\text{Cl} + \text{HCl}$$Vocabulary TrainEnglish Chinese Pinyin alkanes 烷烃 wán tīng combustion 燃烧 rán shāo substitution reaction 取代反应 qǔ dài fǎn yìng ultraviolet light 紫外线 zǐ wài xiàn photochemical reaction 光化学反应 guāng huà xué fǎn yìng activation energy 活化能 huó huà néng 11.5
Alkenes
Syllabus
Core Supplement 1 State that the bonding in alkenes includes a double carbon–carbon covalent bond and that alkenes are unsaturated hydrocarbons 2 Describe the manufacture of alkenes and hydrogen by the cracking of larger alkane molecules using a high temperature and a catalyst 3 Describe the reasons for the cracking of larger alkane molecules 5 State that in an addition reaction only one product is formed 4 Describe the test to distinguish between saturated and unsaturated hydrocarbons by their reaction with aqueous bromine 6 Describe the properties of alkenes in terms of addition reactions with: (a) bromine or aqueous bromine (b) hydrogen in the presence of a nickel catalyst (c) steam in the presence of an acid catalyst and draw the structural or displayed formulae of the products Source: Cambridge International syllabus
Alkenes 烯烃 have a carbon–carbon double bond (C=C), so they are unsaturated hydrocarbons.
Cracking
Large alkane molecules are not very useful. Cracking 裂化 breaks them into smaller, more useful molecules — smaller alkanes and alkenes — using a high temperature and a catalyst 催化剂. Cracking also makes hydrogen 氢气 and provides alkenes for making plastics.
Reactions of alkenes
The C=C double bond makes alkenes reactive. They take part in addition reactions 加成反应, where two molecules join to form a single product.
- Test for unsaturation: shake the compound with bromine 溴 water (which is orange). An alkene turns the bromine water colourless; an alkane does not change it.
- With hydrogen and a nickel 镍 catalyst, an alkene becomes an alkane.
- With steam 蒸汽 and an acid catalyst, an alkene becomes an alcohol.
Vocabulary TrainEnglish Chinese Pinyin alkenes 烯烃 xī tīng cracking 裂化 liè huà catalyst 催化剂 cuī huà jì hydrogen 氢气 qīng qì addition reactions 加成反应 jiā chéng fǎn yìng bromine 溴 xiù nickel 镍 niè steam 蒸汽 zhēng qì 11.6
Alcohols
Syllabus
Core Supplement 1 Describe the manufacture of ethanol by: (a) fermentation of aqueous glucose at 25–35 °C in the presence of yeast and in the absence of oxygen (b) catalytic addition of steam to ethene at 300 °C and 6000 kPa / 60 atm in the presence of an acid catalyst 4 Describe the advantages and disadvantages of the manufacture of ethanol by: (a) fermentation (b) catalytic addition of steam to ethene 2 Describe the combustion of ethanol 3 State the uses of ethanol as: (a) a solvent (b) a fuel Source: Cambridge International syllabus
Alcohols 醇 contain the –OH functional group. The most important one is ethanol 乙醇. There are two ways to make ethanol.
Method Conditions Notes fermentation 发酵 of glucose yeast, 25–35 °C, no oxygen uses renewable sugar, but slow and gives impure ethanol addition of steam to ethene 乙烯 300 °C, 60 atm, acid catalyst fast and pure, but uses petroleum (non-renewable) In fermentation, yeast 酵母 turns glucose 葡萄糖 into ethanol and carbon dioxide.
Ethanol burns well (combustion), so it is used as a fuel. It also dissolves many substances, so it is used as a solvent 溶剂.
Vocabulary TrainEnglish Chinese Pinyin alcohols 醇 chún ethanol 乙醇 yǐ chún fermentation 发酵 fā jiào ethene 乙烯 yǐ xī yeast 酵母 jiào mǔ glucose 葡萄糖 pú táo táng solvent 溶剂 róng jì 11.7
Carboxylic acids
Syllabus
Core Supplement 1 Describe the reaction of ethanoic acid with: (a) metals (b) bases (c) carbonates including names and formulae of the salts produced 2 Describe the formation of ethanoic acid by the oxidation of ethanol: (a) with acidified aqueous potassium manganate(VII) (b) by bacterial oxidation during vinegar production 3 Describe the reaction of a carboxylic acid with an alcohol using an acid catalyst to form an ester Source: Cambridge International syllabus
Carboxylic acids 羧酸 contain the –COOH functional group. Ethanoic acid 乙酸 is the one to know. Like other acids, it reacts with:
- metals 金属 → a salt + hydrogen;
- bases 碱 → a salt 盐 + water;
- carbonates 碳酸盐 → a salt + water + carbon dioxide.
The salts formed are called ethanoates.
Ethanoic acid can be made by the oxidation 氧化 of ethanol, either using acidified potassium manganate(VII) 高锰酸钾, or by bacteria during the making of vinegar 醋.
When a carboxylic acid reacts with an alcohol (using an acid catalyst), it forms an ester 酯.
Vocabulary TrainEnglish Chinese Pinyin carboxylic acids 羧酸 suō suān ethanoic acid 乙酸 yǐ suān metals 金属 jīn shǔ bases 碱 jiǎn salt 盐 yán carbonates 碳酸盐 tàn suān yán oxidation 氧化 yǎng huà potassium manganate(VII) 高锰酸钾 gāo měng suān jiǎ vinegar 醋 cù ester 酯 zhǐ 11.8
Polymers
Syllabus
Core Supplement 1 Define polymers as large molecules built up from many smaller molecules called monomers 6 Identify the repeat units and/or linkages in addition polymers and in condensation polymers 2 Describe the formation of poly(ethene) as an example of addition polymerisation using ethene monomers 7 Deduce the structure or repeat unit of an addition polymer from a given alkene and vice versa 8 Deduce the structure or repeat unit of a condensation polymer from given monomers and vice versa, limited to: (a) polyamides from a dicarboxylic acid and a diamine (b) polyesters from a dicarboxylic acid and a diol 9 Describe the differences between addition and condensation polymerisation 10 Describe and draw the structure of: (a) nylon, a polyamide [image] (b) PET, a polyester [image] The full name for PET, polyethylene terephthalate, is not required 3 State that plastics are made from polymers 4 Describe how the properties of plastics have implications for their disposal 11 State that PET can be converted back into monomers and re-polymerised 5 Describe the environmental challenges caused by plastics, limited to: (a) disposal in landfill sites (b) accumulation in oceans (c) formation of toxic gases from burning 12 Describe proteins as natural polyamides and that they are formed from amino acid monomers with the general structure: [image] where R represents different types of side-chain 13 Describe and draw the structure of proteins as: [image] Source: Cambridge International syllabus
A polymer 聚合物 is a very large molecule built from many small molecules called monomers 单体.
Addition polymerisation
In addition polymerisation 加聚, many unsaturated monomers join together with no other product. For example, many ethene monomers join to make poly(ethene). The small part that repeats along the chain is the repeat unit 重复单元.
In addition polymerisation the C=C bonds open up and many ethene monomers join into a long poly(ethene) chainCondensation polymerisation
In condensation polymerisation 缩聚, monomers join and a small molecule (usually water) is lost each time a bond forms. This makes two important types:
- Polyamides 聚酰胺 are made from a dicarboxylic acid and a diamine. Nylon 尼龙 is a polyamide.
- Polyesters 聚酯 are made from a dicarboxylic acid and a diol. PET is a polyester, and it can be broken back into its monomers and re-made.
Plastics and the environment
Plastics 塑料 are made from polymers. Because many plastics do not break down, getting rid of them is a problem:
- they build up in landfill 填埋 sites;
- they collect in the oceans and harm sea life;
- burning them can make toxic gases.
Proteins
Proteins 蛋白质 are natural polyamides. They are made from amino acid 氨基酸 monomers joined in long chains.
Vocabulary TrainEnglish Chinese Pinyin polymer 聚合物 jù hé wù monomers 单体 dān tǐ addition polymerisation 加聚 jiā jù repeat unit 重复单元 chóng fù dān yuán condensation polymerisation 缩聚 suō jù polyamides 聚酰胺 jù xiān àn nylon 尼龙 ní lóng polyesters 聚酯 jù zhǐ plastics 塑料 sù liào landfill 填埋 tián mái proteins 蛋白质 dàn bái zhì amino acid 氨基酸 ān jī suān -
12 Experimental techniques and chemical analysis
12.1
Experimental design
Syllabus
Core Supplement 1 Name appropriate apparatus for the measurement of time, temperature, mass and volume, including: (a) stop-watches (b) thermometers (c) balances (d) burettes (e) volumetric pipettes (f) measuring cylinders (g) gas syringes 2 Suggest advantages and disadvantages of experimental methods and apparatus 3 Describe a: (a) solvent as a substance that dissolves a solute (b) solute as a substance that is dissolved in a solvent (c) solution as a mixture of one or more solutes dissolved in a solvent (d) saturated solution as a solution containing the maximum concentration of a solute dissolved in the solvent at a specified temperature (e) residue as a substance that remains after evaporation, distillation, filtration or any similar process (f) filtrate as a liquid or solution that has passed through a filter Source: Cambridge International syllabus
Apparatus
You should know which piece of apparatus to use for each measurement:
Measurement Apparatus time stop-watch 秒表 temperature thermometer 温度计 mass balance 天平 volume (accurate) burette 滴定管 or volumetric pipette 移液管 volume (rough) measuring cylinder 量筒 volume of a gas gas syringe 注射器 Key words
These words are used throughout practical chemistry:
- A solvent 溶剂 is a substance that dissolves a solute.
- A solute 溶质 is the substance that dissolves in the solvent.
- A solution 溶液 is a mixture of one or more solutes dissolved in a solvent.
- A saturated solution 饱和溶液 holds the maximum amount of solute that will dissolve at a given temperature.
- A residue 残渣 is the substance left behind after evaporation, distillation or filtration.
- A filtrate 滤液 is the liquid that has passed through a filter.
Vocabulary TrainEnglish Chinese Pinyin stop-watch 秒表 miǎo biǎo thermometer 温度计 wēn dù jì balance 天平 tiān píng burette 滴定管 dī dìng guǎn volumetric pipette 移液管 yí yè guǎn measuring cylinder 量筒 liáng tǒng gas syringe 注射器 zhù shè qì solvent 溶剂 róng jì solute 溶质 róng zhì solution 溶液 róng yè saturated solution 饱和溶液 bǎo hé róng yè residue 残渣 cán zhā filtrate 滤液 lǜ yè 12.2
Acid–base titrations
Syllabus
Core Supplement 1 Describe an acid–base titration to include the use of a: (a) burette (b) volumetric pipette (c) suitable indicator 2 Describe how to identify the end-point of a titration using an indicator Source: Cambridge International syllabus
A titration 滴定 finds the exact volume of one solution that reacts with another.
- Use a volumetric pipette to measure a fixed volume of one solution into a flask.
- Add a few drops of a suitable indicator 指示剂.
- Add the other solution from a burette, slowly, until the colour just changes.
The end-point 终点 is the moment the indicator changes colour, which shows the reaction is exactly complete. You read the burette to find the volume added.
Solution is run from the burette into the flask until the indicator just changes colour (the end-point)
A real titration: solution from the burette is added to the flask, where the indicator has turned orangeVocabulary TrainEnglish Chinese Pinyin titration 滴定 dī dìng indicator 指示剂 zhǐ shì jì end-point 终点 zhōng diǎn 12.3
Chromatography
Syllabus
Core Supplement 1 Describe how paper chromatography is used to separate mixtures of soluble coloured substances, using a suitable solvent 3 Describe how paper chromatography is used to separate mixtures of soluble colourless substances, using a suitable solvent and a locating agent Knowledge of specific locating agents is not required 2 Interpret simple chromatograms to identify: (a) unknown substances by comparison with known substances (b) pure and impure substances 4 State and use the equation for $R_{\text{f}}$: $$R_{\text{f}} = \frac{\text{distance travelled by substance}}{\text{distance travelled by solvent}}$$Source: Cambridge International syllabus
Paper chromatography 纸色谱法 separates a mixture of soluble substances. You put a spot of the mixture near the bottom of the paper, then stand the paper in a solvent. As the solvent rises up the paper, the substances move different distances, so they separate.
As the solvent rises, the substances travel different distances and separate; $R_f$ is the spot distance ($a$) divided by the solvent distance ($b$)
On real chromatograms, each substance in the mixture rises a different distance, leaving a separate coloured spot- For coloured substances you can see the spots directly.
- For colourless substances you must spray a locating agent 显色剂 to make the spots show up.
The finished paper is a chromatogram 色谱图. You can use it to:
- identify an unknown substance by comparing it with known substances;
- tell if a substance is pure (a pure substance gives only one spot).
You can also calculate the $R_{\text{f}}$ value of a spot:
$$R_{\text{f}} = \frac{\text{distance moved by the substance}}{\text{distance moved by the solvent}}$$Vocabulary TrainEnglish Chinese Pinyin paper chromatography 纸色谱法 zhǐ sè pǔ fǎ locating agent 显色剂 xiǎn sè jì chromatogram 色谱图 sè pǔ tú 12.4
Separation and purification
Syllabus
Core Supplement 1 Describe and explain methods of separation and purification using: (a) a suitable solvent (b) filtration (c) crystallisation (d) simple distillation (e) fractional distillation 2 Suggest suitable separation and purification techniques, given information about the substances involved 3 Identify substances and assess their purity using melting point and boiling point information Source: Cambridge International syllabus
You choose a method based on the mixture:
Method Used to separate dissolving in a suitable solvent, then filtration 过滤 an insoluble solid from a liquid crystallisation 结晶 a soluble solid from its solution simple distillation 蒸馏 a solvent (the liquid) from a solution fractional distillation 分馏 two or more liquids with different boiling points
Filtration: the insoluble solid stays on the filter paper (residue) and the liquid passes through (filtrate)
Simple distillation: the solvent boils off, the condenser cools it back to a liquid, and the pure distillate is collected
Fractional distillation adds a fractionating column, so liquids with different boiling points separate cleanlyYou can check the purity of a substance using its melting point 熔点 and boiling point 沸点: a pure substance melts and boils at sharp, fixed temperatures, while impurities lower the melting point and raise the boiling point.
Vocabulary TrainEnglish Chinese Pinyin filtration 过滤 guò lǜ crystallisation 结晶 jié jīng simple distillation 蒸馏 zhēng liú fractional distillation 分馏 fēn liú melting point 熔点 róng diǎn boiling point 沸点 fèi diǎn 12.5
Identifying ions and gases
Syllabus
Core Supplement 1 Describe tests to identify the anions: (a) carbonate, $\text{CO}_3^{2-}$, by reaction with dilute acid and then testing for carbon dioxide gas (b) chloride, $\text{Cl}^-$, bromide, $\text{Br}^-$, and iodide, $\text{I}^-$, by acidifying with dilute nitric acid then adding aqueous silver nitrate (c) nitrate, $\text{NO}_3^-$, reduction with aluminium foil and aqueous sodium hydroxide and then testing for ammonia gas (d) sulfate, $\text{SO}_4^{2-}$, by acidifying with dilute nitric acid and then adding aqueous barium nitrate (e) sulfite, $\text{SO}_3^{2-}$, by reaction with acidified aqueous potassium manganate(VII) 2 Describe tests using aqueous sodium hydroxide and aqueous ammonia to identify the aqueous cations: (a) aluminium, $Al^{3+}$ (b) ammonium, $NH_4^+$ (c) calcium, $Ca^{2+}$ (d) chromium(III), $Cr^{3+}$ (e) copper(II), $Cu^{2+}$ (f) iron(II), $Fe^{2+}$ (g) iron(III), $Fe^{3+}$ (h) zinc, $Zn^{2+}$ 3 Describe tests to identify the gases: (a) ammonia, $NH_3$, using damp red litmus paper (b) carbon dioxide, $CO_2$, using limewater (c) chlorine, $Cl_2$, using damp litmus paper (d) hydrogen, $H_2$, using a lighted splint (e) oxygen, $O_2$, using a glowing splint (f) sulfur dioxide, $SO_2$, using acidified aqueous potassium manganate(VII) 4 Describe the use of a flame test to identify the cations: (a) lithium, $Li^+$ (b) sodium, $Na^+$ (c) potassium, $K^+$ (d) calcium, $Ca^{2+}$ (e) barium, $Ba^{2+}$ (f) copper(II), $Cu^{2+}$ Source: Cambridge International syllabus
Tests for anions
An anion 阴离子 is a negative ion.
Anion Test Result carbonate 碳酸盐 ($\text{CO}_3^{2-}$) add dilute acid fizzes; the gas turns limewater milky (carbon dioxide 二氧化碳) chloride 氯化物 ($\text{Cl}^-$) add dilute nitric acid 硝酸, then silver nitrate 硝酸银 white precipitate bromide 溴化物 ($\text{Br}^-$) add dilute nitric acid, then silver nitrate cream precipitate iodide 碘化物 ($\text{I}^-$) add dilute nitric acid, then silver nitrate yellow precipitate nitrate 硝酸盐 ($\text{NO}_3^-$) add aluminium 铝 foil and sodium hydroxide 氢氧化钠, warm ammonia 氨气 gas given off sulfate 硫酸盐 ($\text{SO}_4^{2-}$) add dilute nitric acid, then barium nitrate 硝酸钡 white precipitate sulfite 亚硫酸盐 ($\text{SO}_3^{2-}$) add acidified potassium manganate(VII) 高锰酸钾 purple colour fades Tests for cations
A cation 阳离子 is a positive ion. Add aqueous sodium hydroxide, or aqueous ammonia, and look at the precipitate 沉淀 formed.
Cation With sodium hydroxide With aqueous ammonia aluminium ($\text{Al}^{3+}$) white, dissolves in excess white, stays ammonium 铵 ($\text{NH}_4^+$) ammonia gas when warmed — calcium 钙 ($\text{Ca}^{2+}$) white, stays no precipitate chromium(III) 铬 ($\text{Cr}^{3+}$) green, dissolves in excess green, stays copper(II) 铜 ($\text{Cu}^{2+}$) light blue, stays light blue, dissolves to deep blue iron(II) 铁 ($\text{Fe}^{2+}$) green, stays green, stays iron(III) ($\text{Fe}^{3+}$) red-brown, stays red-brown, stays zinc 锌 ($\text{Zn}^{2+}$) white, dissolves in excess white, dissolves in excess Tests for gases
Gas Test Result ammonia ($\text{NH}_3$) damp red litmus 石蕊 paper turns blue carbon dioxide ($\text{CO}_2$) bubble through limewater 石灰水 turns milky chlorine 氯气 ($\text{Cl}_2$) damp litmus paper bleached white hydrogen 氢气 ($\text{H}_2$) a lighted splint burns with a squeaky pop oxygen 氧气 ($\text{O}_2$) a glowing splint relights sulfur dioxide ($\text{SO}_2$) acidified potassium manganate(VII) purple colour fades Flame tests
A flame test 焰色试验 identifies some metal cations by the colour they give to a flame:
Cation Flame colour lithium 锂 ($\text{Li}^+$) red sodium 钠 ($\text{Na}^+$) yellow potassium 钾 ($\text{K}^+$) lilac (purple) calcium ($\text{Ca}^{2+}$) orange-red barium 钡 ($\text{Ba}^{2+}$) light green copper(II) ($\text{Cu}^{2+}$) blue-green Vocabulary TrainEnglish Chinese Pinyin anion 阴离子 yīn lí zi carbonate 碳酸盐 tàn suān yán carbon dioxide 二氧化碳 èr yǎng huà tàn chloride 氯化物 lǜ huà wù nitric acid 硝酸 xiāo suān silver nitrate 硝酸银 xiāo suān yín bromide 溴化物 xiù huà wù iodide 碘化物 diǎn huà wù nitrate 硝酸盐 xiāo suān yán aluminium 铝 lǚ sodium hydroxide 氢氧化钠 qīng yǎng huà nà ammonia 氨气 ān qì sulfate 硫酸盐 liú suān yán barium nitrate 硝酸钡 xiāo suān bèi sulfite 亚硫酸盐 yà liú suān yán potassium manganate(VII) 高锰酸钾 gāo měng suān jiǎ cation 阳离子 yáng lí zi precipitate 沉淀 chén diàn ammonium 铵 ǎn calcium 钙 gài chromium 铬 gè copper 铜 tóng iron 铁 tiě zinc 锌 xīn litmus 石蕊 shí ruǐ limewater 石灰水 shí huī shuǐ chlorine 氯气 lǜ qì hydrogen 氢气 qīng qì oxygen 氧气 yǎng qì flame test 焰色试验 yàn sè shì yàn lithium 锂 lǐ sodium 钠 nà potassium 钾 jiǎ barium 钡 bèi