Balancing redox and agents
Balancing redox and agents
- Oxidation numbers help balance redox equations.
- A special case is disproportionation.
- And every redox reaction has an oxidising and a reducing agent.
Balancing with oxidation numbers
- find the element whose number rises (oxidised) and the one whose number falls (reduced).
- the total rise = total fall (every electron lost is gained somewhere).
- choose the ratio so they match, then balance the rest.
Practice
When balancing a redox equation using oxidation numbers:
Every electron lost is gained, so the total increase in oxidation number equals the total decrease.
Disproportionation
- Disproportionation is when the same element is both oxidised and reduced at once.
- E.g. chlorine + cold water: some Cl atoms are reduced to $\text{Cl}^{-}$ ($-1$) and others oxidised to $\text{ClO}^{-}$ ($+1$).
Practice
Disproportionation is a reaction in which:
In disproportionation one element goes both up and down in oxidation number (e.g. Cl₂ → Cl⁻ and ClO⁻).
Oxidising and reducing agents
- an oxidising agent takes electrons from another species — so it is itself reduced.
- a reducing agent gives electrons to another species — so it is itself oxidised.
Practice
An oxidising agent:
An oxidising agent removes electrons from another species, so it gains electrons and is reduced itself.
Practice
A reducing agent:
A reducing agent donates electrons, causing reduction of the other species while being oxidised itself.
You've got it
Key idea
- balance redox by making the total rise = total fall in oxidation number
- disproportionation: the same element is both oxidised and reduced (Cl₂ → Cl⁻ + ClO⁻)
- oxidising agent takes electrons (itself reduced); reducing agent gives electrons (itself oxidised)