Reactions across Period 3
Reactions across Period 3
- The Period 3 elements react with oxygen, chlorine and (some) water.
- The products are oxides and chlorides.
- The element's oxidation number rises across the period.
With oxygen and chlorine
- With oxygen: e.g. $2\text{Mg} + \text{O}_2 \rightarrow 2\text{MgO}$, $\text{S} + \text{O}_2 \rightarrow \text{SO}_2$.
- With chlorine: e.g. $2\text{Na} + \text{Cl}_2 \rightarrow 2\text{NaCl}$, $2\text{Al} + 3\text{Cl}_2 \rightarrow 2\text{AlCl}_3$.
Practice
The reaction of sodium with chlorine gives:
Sodium burns in chlorine to form sodium chloride: 2Na + Cl₂ → 2NaCl.
With water
- Only Na and Mg react: $2\text{Na} + 2\text{H}_2\text{O} \rightarrow 2\text{NaOH} + \text{H}_2$.
- Sodium reacts fast; magnesium reacts only very slowly with cold water.
Practice
Which Period 3 elements react with water?
Only Na and Mg react with water; sodium reacts fast, magnesium only very slowly with cold water.
Oxidation numbers
- The element's oxidation number in its oxide/chloride rises across the period.
- It equals the number of outer-shell electrons used in bonding.
| Oxide | $\text{Na}_2\text{O}$ | $\text{MgO}$ | $\text{Al}_2\text{O}_3$ | $\text{P}_4\text{O}_{10}$ | $\text{SO}_3$ |
|---|---|---|---|---|---|
| ox. number | +1 | +2 | +3 | +5 | +6 |
Practice
The oxidation number of the Period 3 element in its oxide rises across the period because it equals:
Going across, each element uses more valence electrons, so its oxidation number rises (+1 for Na up to +6 for S in SO₃).
Practice
In Al₂O₃, the oxidation number of aluminium is:
Na₂O is +1, MgO +2, Al₂O₃ +3 — the oxidation number rises across the period.
You've got it
Key idea
- elements react with oxygen and chlorine to form oxides and chlorides
- with water, only Na (fast) and Mg (slow) react
- the element's oxidation number rises across the period (= outer electrons used)