The shape of benzene
The shape of benzene
- Benzene is a flat, regular hexagon.
- Its electrons are delocalised into one ring system.
- This makes benzene unusually stable.
Practice
Benzene is a flat, regular hexagon.
Its sp² σ framework and delocalised π system make it planar and symmetrical.
The bonding
- Each carbon is sp² hybridised, making sigma bonds to two carbons and one hydrogen — the flat hexagon.
- Each carbon's leftover p-orbital electron overlaps sideways all the way round, making one delocalised pi system above and below the ring.
- Because the electrons are shared evenly, all six C–C bonds are the same length.
Practice
Each carbon in benzene is:
sp² carbons give the flat hexagon; the leftover p-orbitals form the delocalised π system.
Practice
In benzene, all six C–C bonds are the same length because:
The single delocalised π system spreads the electrons evenly, so every C–C bond is identical.
Evidence: hydrogenation
- Adding $\text{H}_2$ to one C=C (cyclohexene) releases about $120\ \text{kJ}/\text{mol}$, so a Kekulé ring of three double bonds should release $\approx 360\ \text{kJ}/\text{mol}$.
- Real benzene releases only $208\ \text{kJ}/\text{mol}$ — about $152\ \text{kJ}/\text{mol}$ more stable than the model predicts. That extra stability is the delocalisation.
Practice
The enthalpy of hydrogenation shows benzene is more stable than the Kekulé model because real benzene releases:
Real benzene releases only 208 kJ/mol, ~152 kJ/mol less than the 360 predicted — the extra stability of delocalisation.
You've got it
Key idea
- benzene is a flat, regular hexagon of sp² carbons (a σ framework)
- the p-orbitals overlap into one delocalised π system, so all six C–C bonds are equal
- hydrogenation evidence: real benzene ($-208\ \text{kJ}/\text{mol}$) is far more stable than the Kekulé model ($-360$), by ≈ 152 kJ/mol